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java - Does array changes in method?

When I write like this:

public class test {

    void mainx()
    {
        int fyeah[] = {2, 3, 4};
        smth(fyeah);
        System.out.println("x"+fyeah[0]);
    }

    void smth(int[] fyeah)
    {
        fyeah[0] = 22;
    }
}

It prints x22;

When I write like this:

public class test {

    void mainx()
    {
        int fyeah = 5;
        smth(fyeah);
        System.out.println("x"+fyeah);
    }

    void smth(int fyeah)
    {
        fyeah = 22;
    }
}

It doesn't print x22, but prints x5.

Why, in the second version function, doesn't the value change? Does it change values only for array elements?

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1 Answer

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by (71.8m points)

The fyeah variable in your first example contains a reference to an array (not an array), while the fyeah integer in your second example contains an integer.

Since Java passes everything by value the following will happen:

In the array case: A copy of the array reference will be sent, and the original array will be changed.

In the int case: A copy of the integer will be changed, and the original integer will not be changed.


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