uiviewcontroller - Make property of type and also conform to protocol in Swift

Question

I would like to make a property that is of a certain type and also conforms to a protocol, which I would have done in Objective-C like this:

@property (nonatomic) UIViewController<CustomProtocol> *controller;

What I am looking for is to specify that the property can be set with an object of type UIViewController that also conforms to CustomProtocol, so that it's clear what the base class is. I know I could probably just use a short class stub to get the same results, i.e.

class CustomViewController : UIViewController, CustomProtocol {}

But this doesn't seem like the cleanest way to do it.

Answer 1

This is now possible using the built-in composition:

var children = [UIViewController & NavigationScrollable]()