validation - Java: How to parse a date strictly?

Question

SimpleDateFormat is a very kind parser that rolls the resulting date instead of throwing an error. How can I parse a date strictly without regexps etc?

fmt = new SimpleDateFormat("dd.MM.yyyy")
fmt.parse("10.11.2012")   // it works
fmt.parse("10.1150.2012") // it works but it's unwanted

Answer 1

fmt.setLenient(false); is what you're looking for.