haskell - Function to output function name

Question

Is it possible in Haskell to implement a function which returns its own function name?

A possible type could be (a -> b) -> String.

Answer 1

You want a function that takes a function argument, and returns the definition site variable name that corresponds to the name of that function?

This isn't possibly without meta-programming, which is usually a sign you're doing something wrong :). But assuming you're not, one way to achieve something in the right direction is via Template Haskell, which can get at unique names (how the compiler names things). E.g.

Prelude Language.Haskell.TH> :set -XTemplateHaskell
Prelude Language.Haskell.TH> let f x y = x + y
Prelude Language.Haskell.TH> $( stringE . show =<< reify 'f )

     "VarI f_1627394057
                (ForallT [PlainTV a_1627394063]
                         [ClassP GHC.Num.Num [VarT a_1627394063]]
                              (AppT (AppT ArrowT (VarT a_1627394063)) 
                                    (AppT (AppT ArrowT (VarT a_1627394063)) 
                                         (VarT a_1627394063)))) 
                         Nothing (Fixity 9 InfixL)"

And now we know a lot about the variable. So you can play games by passing a Name to the function (via 'f) rather than f itself.

You are certainly in the world of reflection and meta-programming though, so it would help to know more about what you are trying to do.