Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
623 views
in Technique[技术] by (71.8m points)

random - JavaScript - How to randomly sample items without replacement?

JavaScript

I've tried searching for something like this, but I am not able to find it.

It's a simple idea:

a. Take a random number between 0 to 10.

b. Let's say the random number rolled is a 3.

c. Then, save the number (the 3).

d. Now, take another random number again between 0 to 10, but it can't be the 3, because it has already appeared.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

One solution is to generate an array (a "bucket") with all the values you want to pick, in this case all numbers from 0 to 10. Then you pick one randomly from the array and remove it from the bucket. Note that the example below doesn't check if the bucket is empty, so if you call the function below more than 10 times you will get an error.

var bucket = [];

for (var i=0;i<=10;i++) {
    bucket.push(i);
}

function getRandomFromBucket() {
   var randomIndex = Math.floor(Math.random()*bucket.length);
   return bucket.splice(randomIndex, 1)[0];
}

// will pick a random number between 0 and 10, and can be called 10 times
console.log(getRandomFromBucket());

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...