Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
346 views
in Technique[技术] by (71.8m points)

java - JTable row color depending on Value in model?

I have this code in my Table model:

public class DocumentProjectTableModel extends AbstractTableModel{

    private List<MyDocument> myDocuments;
    public String getValueAt(int row, int column) {
            String toReturn = null;
            MyDocument myDocument = myDocuments.get(row);
            SimpleDateFormat format = new SimpleDateFormat("dd.MM.yyyy");

            switch (column) {
                case 0:
                    if(myDocument.getProject().getRegDate()!=null) toReturn = format.format(myDocument.getProject().getRegDate());
                    break;
                case 1:
                    toReturn = myDocument.getProject().getRegNum();
                    break;
                case 2:
                    toReturn = myDocument.getProject().getDescription();
                    break;
                case 3:
                    toReturn = myDocument.getProject().getShortName();
                    break;
                case 4:
                    toReturn = myDocument.getProject().getSecondName()+myDocument.getProject().getFirstName()+myDocument.getProject().getMiddleName();
                    break;

            }
            return toReturn;
        }
//  some other stuff is not shown

I want to change background color of each row, for example if myDocument.getIsRegistered() == true, I want this row to have yellow background, if myDocument.getIsValid == false row is blue and so on.

I've found examples that recolor rows depending on values in JTable. But getIsValid and getIsRegistered() aren't actually displayed, they exist only in model. Any advice or example would really help. thanks in advance.

update. my TableCellRenderer:

public class MyTableCellRenderer extends JLabel implements TableCellRenderer {

    public Component getTableCellRendererComponent(JTable table, Object value,
            boolean isSelected, boolean hasFocus, int rowIndex, int vColIndex) {
        String actualValue = (String) value;
        // Set the colors as per the value in the cell...
        if(actualValue.equals("lifesucks") ){
            setBackground(Color.YELLOW);
        }
        return this;
    }
}

using renderer:

            int vColIndex = 0;
            TableColumn col = resultTable.getColumnModel().getColumn(vColIndex);
            col.setCellRenderer(new MyTableCellRenderer());
 resultTable.setModel(new DocumentProjectTableModel(docs));

table is shown as usual no yellow color. why?

update2.

resultTable=new JTable(new DocumentProjectTableModel(docs)){
            public Component prepareRenderer(TableCellRenderer renderer, int row, int column)
            {
                Component c = super.prepareRenderer(renderer, row, column);
                //  Color row based on a cell value
                if (!isRowSelected(row)) {
                    c.setBackground(getBackground());
                    int modelRow = convertRowIndexToModel(row);
                    String type = (String) getModel().getValueAt(modelRow, 0);

                        c.setBackground(Color.GREEN);
                }
                return c;
            }
        };

table is empty:(

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Since you want to color an entire row, its easier to use Table Row Rendering than it is to create muuliple custom renderers.

I've found examples that recolor rows depending on values in JTable. But getIsValid and getIsRegistered() aren't actually displayed, they exist only in model

You can still access the model from the table. You just use:

table.getModel().getValueAt(...);

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...