c++ - Derived class Private method is getting called

Question

I have a Base class pointer pointing to derived class object. The method foo() is public in base class but private in derived class. Base class foo() is virtual. So when i call foo() from Base class pointer, Vptr Table has the address of derived class foo(), BUT its private in Derived class ...so how is it getting called.??

I understand Run time polymorphism and i also understand that the Access specifiers work for compile time and Virtual concept works at run time. So there shall be No Compiler error.

My question is : Is this is a loop hole through which we can call private methods of Derived class ? or Its expected to behave this way. Any good Explanation for this behavior.

Thanks a lot in advance.

CODE :

class A
{
public:
    virtual void foo()
    {
        std::cout << "In A";
    }
};


class B:public A
{
private:
    void foo()
    {
       std::cout << "In B ??? Its Private Method :-( ";
    }
};

int main()
{
    A* ptr = new B();
    ptr->foo();
    return 0;
}

Answer 1

It's private method, but since it's virtual - it can be called.

n3690 11.5/1

The access rules (Clause 11) for a virtual function are determined by its declaration and are not affected by the rules for a function that later overrides it.

Why this? Since

n3690 11.5/2

Access is checked at the call point using the type of the expression used to denote the object for which the member function is called (B* in the example above). The access of the member function in the class in which it was defined (D in the example above) is in general not known.