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design patterns - Java: Lazy Initializing Singleton

The pattern to create singletons seems to be something like:

public class Singleton {
    private static final Singleton instance = new Singleton();
    private Singleton(){
    }

    public static Singleton getInstance()
    {
        return instance;
    }
}

However my problem is how do you Unit with a class like this if the Singleton Constructor does something that is not unit test friendly e.g. calls external service , jndi lookup etc.

I would think i could refactor it like:

public class Singleton {
    private static Singleton instance;
    private Singleton(){
    }

    public synchronized static Singleton getInstance()
    {
        if(instance == null)
             instance = new Singleton();
        return instance;
    }

     //for the unit tests
     public static void setInstance(Singleton s)
     {
          instancce = s;
     }
}

The problem now is that just for unit testability I have forced the getInstance to be synchronized so just for testing aspect it will have a negative impact on the real application. Is there a way around it, it seems any other sort of lazy initialization will not work because of the broken nature of double locking pattern in java.

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1 Answer

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You can use an enum as a Singleton

enum Singleton {
    INSTANCE;
}

Say your singleton does something undesirable in unit tests, you can;

// in the unit test before using the Singleton, or any other global flag.
System.setProperty("unit.testing", "true");

Singleton.INSTANCE.doSomething();

enum Singleton {
    INSTANCE;
    {
        if(Boolean.getBoolean("unit.testing")) {
           // is unit testing.
        } else {
           // normal operation.
        }
    }
}

Note: there is no synchronised blocks or explicit lock needed. The INSTANCE will not be loaded until the .class is accessed and not initialised until a member is used. provided you only use Singleton.INSTANCE and not Singleton.class there won't be a problem with the value used to initialise changing later.


Edit: if you use just the Singleton.class this might not initialise the class. It doesn't in this example on Java 8 update 112.

public class ClassInitMain {
    public static void main(String[] args) {
        System.out.println("Printing a class reference");
        Class clazz = Singleton.class;
        System.out.println("clazz = " + clazz);
        System.out.println("
Using an enum value");
        Singleton instance = Singleton.INSTANCE;
    }

    static enum Singleton {
        INSTANCE;

        Singleton() {
            System.out.println(getClass() + " initialised");
        }
    }
}

prints

Printing a class reference
clazz = class ClassInitMain$Singleton

Using an enum value
class ClassInitMain$Singleton initialised

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