This is a working function for converting the data to OHLC:
function convertToOHLC(data) {
data.sort((a, b) => d3.ascending(a.date, b.date));
var result = [];
var format = d3.timeFormat("%Y-%m-%d");
data.forEach(d => d.date = format(new Date(d.date * 1000)));
var allDates = [...new Set(data.map(d => d.date))];
allDates.forEach(d => {
var tempObject = {};
var filteredData = data.filter(e => e.date === d);
tempObject.date = d;
tempObject.open = filteredData[0].price;
tempObject.close = filteredData[filteredData.length - 1].price;
tempObject.high = d3.max(filteredData, e => e.price);
tempObject.low = d3.min(filteredData, e => e.price);
result.push(tempObject);
});
return result;
};
Here is your updated fiddle: https://jsfiddle.net/mg9v89r2/
Step by step explanation:
First, we sort the original data array by the dates:
data.sort((a, b) => d3.ascending(a.date, b.date));
That's an important step when we deal with open
and close
later.
After that, we convert the milliseconds to dates, as strings:
var format = d3.timeFormat("%Y-%m-%d");
data.forEach(d => d.date = format(new Date(d.date * 1000)));
Doing this, we can filter all objects belonging to a given day. First, we create an array with all different days in your data:
var allDates = [...new Set(data.map(d => d.date))];
For each day of that array, we will call a function that will populate an empty array, named results
:
allDates.forEach(d => {
var tempObject = {};
var filteredData = data.filter(e => e.date === d);
tempObject.date = d;
tempObject.open = filteredData[0].price;
tempObject.close = filteredData[filteredData.length - 1].price;
tempObject.high = d3.max(filteredData, e => e.price);
tempObject.low = d3.min(filteredData, e => e.price);
result.push(tempObject);
});
In the above forEach
, we create an empty object, and for each day in our allDates
array, we filter the data:
var filteredData = data.filter(e => e.date === d);
And populate an temporary object with it:
var tempObject = {};
tempObject.date = d;
tempObject.open = filteredData[0].price;
tempObject.close = filteredData[filteredData.length - 1].price;
tempObject.high = d3.max(filteredData, e => e.price);
tempObject.low = d3.min(filteredData, e => e.price);
After each iteration, we push that temporary object into results
:
result.push(tempObject);
Finally, we return results
.
That huge data array in your fiddle, surprisingly, has only 2 days of data.