You may use the .zip
function for that
list1.zip(list2){ a,b -> listOf(a,b)}.flatten()
The only problem is that it will only process elements, with both sets, so if (like in the example) let's have different size - it will not work
The alternative could be to add specific markers and filter them or to just use iterators for that. I found an elegant solution with sequence{..}
function
val result = sequence {
val first = list1.iterator()
val second = list2.iterator()
while (first.hasNext() && second.hasNext()) {
yield(first.next())
yield(second.next())
}
yieldAll(first)
yieldAll(second)
}.toList()
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