sql - Combining 3 SELECT statements to output 1 table

Question

I have three queries with results.

Query 1:

SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 1 AND workid < 557 AND workid > 188
GROUP BY employeeid, clientid ORDER BY clientid ASC;

employeeid | clientid | under_over_1
------------+----------+--------------
          1 |        3 |         0.54
          1 |        4 |         0.47
          1 |        6 |         0.45
          1 |        7 |         0.59
          . |        . |           .
          . |        . |           .

Query 2:

SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1.31666666666667, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 2
GROUP BY employeeid, clientid ORDER BY clientid ASC;

 employeeid | clientid | under_over_1
------------+----------+--------------
          2 |        2 |         1.01
          2 |        3 |         0.21
          2 |        4 |         0.71
          2 |        6 |         0.68
          . |        . |           .
          . |        . |           .

Query: 3

SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1.31666666666667, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 3
GROUP BY employeeid, clientid ORDER BY clientid ASC;

 employeeid | clientid | under_over_1
------------+----------+--------------
          3 |        4 |         0.70
          3 |        6 |         0.54
          3 |        7 |         1.03
          3 |       11 |         0.74
          . |        . |           .
          . |        . |           .

I want to output one table with the result of all three queries such as (I am sorry but I have to write more here so I can submit this post. I hope this is enough;-)):

employeeid | clientid | under_over_1
------------+----------+--------------
          1 |        3 |         0.54
          1 |        4 |         0.47
          1 |        6 |         0.45
          1 |        7 |         0.59
          . |        . |           .
          . |        . |           .
          2 |        2 |         1.01
          2 |        3 |         0.21
          2 |        4 |         0.71
          2 |        6 |         0.68
          . |        . |           .
          . |        . |           .
          3 |        4 |         0.70
          3 |        6 |         0.54
          3 |        7 |         1.03
          3 |       11 |         0.74
          . |        . |           .
          . |        . |           .

I tried UNION ALL as in

SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 1 AND workid < 557 AND workid > 188
GROUP BY employeeid, clientid ORDER BY clientid ASC

UNION ALL

SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1.31666666666667, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 3
GROUP BY employeeid, clientid ORDER BY clientid ASC

UNION ALL

SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1.31666666666667, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 2
GROUP BY employeeid, clientid ORDER BY clientid ASC;

However, I get the following error:

ERROR:  syntax error at or near "UNION"
LINE 7: UNION ALL

I am not sure why this is wrong or whether UNION ALL is the right approach here. Anyone have a clue?

Answer 1

Remove all the ORDER BYs. Then use the resulting query as a derived table. To retain the order you presumably want, you can then use a CASE expression to map the employeeid to and integer determining the order:

SELECT x.employeeid,
       x.clientid,
       x.under_over_1
       FROM (<your UNION ALL query without the ORDER BYs>) x
       ORDER BY CASE x.employeeid
                  WHEN 1 THEN
                    1
                  WHEN 2 THEN
                    3
                  WHEN 3 THEN
                    2
                END,
                x.clientid;