java - Must type multiple times, before scanner reads input

Question

If I run this code

Scanner sc = new Scanner();
while (true) {
        if (sc.next().equals("1"))
            System.out.println("--1--");

        else if (sc.next().equals("2"))
            System.out.println("--2--");

        else if (sc.next().equals("3"))
            System.out.println("--3--");

        else if (sc.next().equals("4"))
            System.out.println("--4--");

        else if (sc.next().equals("help"))
            System.out.println("--help--");
    }

It will not read the first time I type enter. I have to type 2-4 times before it reads the input. A session could look like this:

1
1
1
1
--1--
3
3
--3--
help
2
1
help
--help--

No matter what I type, it will only read the last input of the four inputs. Sometimes it reads after two inputs. I'm really confused about this. Should I instead use multiple scanners?

Answer 1

Your concepts are wrong here.

Each time you ask for sc.next() it will wait for the input. If that input is equal to what you want it to be, then the code is executed.

You can correct this by storing sc.next() in a String variable, and then comparing it.

Here: if (sc.next().equals("1")) it asks for an input.

If that input is 1 then the code is executed and --1-- is printed out. Else, it jumps to this: if (sc.next().equals("2")). Now if the input is 2 then the code to print --2-- is executed. Else, it jumps to if (sc.next().equals("3")) and so on.

You can correct this by:

• storing sc.next() in a String variable, and then comparing it.
• using a switch-case block to compare the input.