Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
424 views
in Technique[技术] by (71.8m points)

sql - Select newest records that have distinct Name column

I did search around and I found this SQL selecting rows by most recent date with two unique columns Which is so close to what I want but I can't seem to make it work.

I get an error Column 'ID' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.

I want the newest row by date for each Distinct Name

Select ID,Name,Price,Date
From  table
Group By Name
Order By Date ASC

Here is an example of what I want

Table

ID Name Price Date
0 A 10 2012-05-03
1 B 9 2012-05-02
2 A 8 2012-05-04
3 C 10 2012-05-03
4 B 8 2012-05-01
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)
Select ID,Name, Price,Date
From  temp t1
where date = (select max(date) from temp where t1.name =temp.name)
order by date desc

Here is a SQL Fiddle with a demo of the above


Or as Conrad points out you can use an INNER JOIN (another SQL Fiddle with a demo) :

SELECT t1.ID, t1.Name, t1.Price, t1.Date 
FROM   temp t1 
INNER JOIN 
(
    SELECT Max(date) date, name
    FROM   temp 
    GROUP BY name 
) AS t2 
    ON t1.name = t2.name
    AND t1.date = t2.date 
ORDER BY date DESC 

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

2.1m questions

2.1m answers

60 comments

57.0k users

...