Finally, I managed to write my own implementation of ICP in Python, using the sklearn and opencv libraries.
The function takes two datasets, an initial relative pose estimation and the desired number of iterations.
It returns a transformation matrix that transforms the first dataset to the second.
Enjoy!
import cv2
import numpy as np
import matplotlib.pyplot as plt
from sklearn.neighbors import NearestNeighbors
def icp(a, b, init_pose=(0,0,0), no_iterations = 13):
'''
The Iterative Closest Point estimator.
Takes two cloudpoints a[x,y], b[x,y], an initial estimation of
their relative pose and the number of iterations
Returns the affine transform that transforms
the cloudpoint a to the cloudpoint b.
Note:
(1) This method works for cloudpoints with minor
transformations. Thus, the result depents greatly on
the initial pose estimation.
(2) A large number of iterations does not necessarily
ensure convergence. Contrarily, most of the time it
produces worse results.
'''
src = np.array([a.T], copy=True).astype(np.float32)
dst = np.array([b.T], copy=True).astype(np.float32)
#Initialise with the initial pose estimation
Tr = np.array([[np.cos(init_pose[2]),-np.sin(init_pose[2]),init_pose[0]],
[np.sin(init_pose[2]), np.cos(init_pose[2]),init_pose[1]],
[0, 0, 1 ]])
src = cv2.transform(src, Tr[0:2])
for i in range(no_iterations):
#Find the nearest neighbours between the current source and the
#destination cloudpoint
nbrs = NearestNeighbors(n_neighbors=1, algorithm='auto',
warn_on_equidistant=False).fit(dst[0])
distances, indices = nbrs.kneighbors(src[0])
#Compute the transformation between the current source
#and destination cloudpoint
T = cv2.estimateRigidTransform(src, dst[0, indices.T], False)
#Transform the previous source and update the
#current source cloudpoint
src = cv2.transform(src, T)
#Save the transformation from the actual source cloudpoint
#to the destination
Tr = np.dot(Tr, np.vstack((T,[0,0,1])))
return Tr[0:2]
Call it like this:
#Create the datasets
ang = np.linspace(-np.pi/2, np.pi/2, 320)
a = np.array([ang, np.sin(ang)])
th = np.pi/2
rot = np.array([[np.cos(th), -np.sin(th)],[np.sin(th), np.cos(th)]])
b = np.dot(rot, a) + np.array([[0.2], [0.3]])
#Run the icp
M2 = icp(a, b, [0.1, 0.33, np.pi/2.2], 30)
#Plot the result
src = np.array([a.T]).astype(np.float32)
res = cv2.transform(src, M2)
plt.figure()
plt.plot(b[0],b[1])
plt.plot(res[0].T[0], res[0].T[1], 'r.')
plt.plot(a[0], a[1])
plt.show()