This is a bare-bones example of how to use scipy.optimize.leastsq
:
import numpy as np
import scipy.optimize as optimize
import matplotlib.pylab as plt
def func(kd,p0,l0):
return 0.5*(-1-((p0+l0)/kd) + np.sqrt(4*(l0/kd)+(((l0-p0)/kd)-1)**2))
The sum of the squares of the residuals
is the function of kd
we're trying to minimize:
def residuals(kd,p0,l0,PLP):
return PLP - func(kd,p0,l0)
Here I generate some random data. You'd want to load your real data here instead.
N=1000
kd_guess=3.5 # <-- You have to supply a guess for kd
p0 = np.linspace(0,10,N)
l0 = np.linspace(0,10,N)
PLP = func(kd_guess,p0,l0)+(np.random.random(N)-0.5)*0.1
kd,cov,infodict,mesg,ier = optimize.leastsq(
residuals,kd_guess,args=(p0,l0,PLP),full_output=True,warning=True)
print(kd)
yields something like
3.49914274899
This is the best fit value for kd
found by optimize.leastsq
.
Here we generate the value of PLP
using the value for kd
we just found:
PLP_fit=func(kd,p0,l0)
Below is a plot of PLP
versus p0
. The blue line is from data, the red line is the best fit curve.
plt.plot(p0,PLP,'-b',p0,PLP_fit,'-r')
plt.show()