Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
128 views
in Technique[技术] by (71.8m points)

java - Finding Points contained in a Path in Android

Is there a reason that they decided not to add the contains method (for Path) in Android?

I'm wanting to know what points I have in a Path and hoped it was easier than seen here:

How can I tell if a closed path contains a given point?

Would it be better for me to create an ArrayList and add the integers into the array? (I only check the points once in a control statement) Ie. if(myPath.contains(x,y)

So far my options are:

  • Using a Region
  • Using an ArrayList
  • Extending the Class
  • Your suggestion

I'm just looking for the most efficient way I should go about this

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

I came up against this same problem a little while ago, and after some searching, I found this to be the best solution.

Java has a Polygon class with a contains() method that would make things really simple. Unfortunately, the java.awt.Polygonclass is not supported in Android. However, I was able to find someone who wrote an equivalent class.

I don't think you can get the individual points that make up the path from the Android Path class, so you will have to store the data in a different way.

The class uses a Crossing Number algorithm to determine whether or not the point is inside of the given list of points.

/**
 * Minimum Polygon class for Android.
 */
public class Polygon
{
    // Polygon coodinates.
    private int[] polyY, polyX;

    // Number of sides in the polygon.
    private int polySides;

    /**
     * Default constructor.
     * @param px Polygon y coods.
     * @param py Polygon x coods.
     * @param ps Polygon sides count.
     */
    public Polygon( int[] px, int[] py, int ps )
    {
        polyX = px;
        polyY = py;
        polySides = ps;
    }

    /**
     * Checks if the Polygon contains a point.
     * @see "http://alienryderflex.com/polygon/"
     * @param x Point horizontal pos.
     * @param y Point vertical pos.
     * @return Point is in Poly flag.
     */
    public boolean contains( int x, int y )
    {
        boolean oddTransitions = false;
        for( int i = 0, j = polySides -1; i < polySides; j = i++ )
        {
            if( ( polyY[ i ] < y && polyY[ j ] >= y ) || ( polyY[ j ] < y && polyY[ i ] >= y ) )
            {
                if( polyX[ i ] + ( y - polyY[ i ] ) / ( polyY[ j ] - polyY[ i ] ) * ( polyX[ j ] - polyX[ i ] ) < x )
                {
                    oddTransitions = !oddTransitions;          
                }
            }
        }
        return oddTransitions;
    }  
}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...