python - Time difference in seconds from numpy.timedelta64

Question

How to get time difference in seconds from numpy.timedelta64 variable?

time1 = '2012-10-05 04:45:18'
time2 = '2012-10-05 04:44:13'
dt = np.datetime64(time1) - np.datetime64(time2)
print dt

0:01:05

I'd like to convert dt to number (int or float) representing time difference in seconds.

Answer 1

To get number of seconds from numpy.timedelta64() object using numpy 1.7 experimental datetime API:

seconds = dt / np.timedelta64(1, 's')