Postgres
In Postgres, this can be achieved with the following query.
SELECT DISTINCT ON ("group") * FROM projects
ORDER BY "group", date DESC, id DESC
Because the date
column might not be unique here, I have added an additional ORDER BY
clause on id DESC
to break ties in favor of the record with the higher ID, in case two records in a group have the same date. You might instead want to use another column like the date/time of the last update or so, that depends on your use case.
Moving on, ActiveRecord unfortunately has no API for DISTINCT ON
, but we can still use plain SQL with select
:
Project.select('DISTINCT ON ("group") *').order(:group, date: :desc, id: :desc)
or if you prefer using ARel instead of having raw SQL:
p = Project.arel_table
Project.find_by_sql(
p.project(p[Arel.star])
.distinct_on(p[:group])
.order(p[:group], p[:date].desc, p[:id].desc)
)
MySQL
For other databases like MySQL this is unfortunately not as convenient. There are a variety of solutions available, see for example this answer.
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