I have no clue about what the [] option does in cout
This is actually not a cout
option, what is happening is that "
"
is a string literal. A string literal has the type array of n const char, the []
is simply an index into an array of characters which in this case contains:
note
is appended to all string literals.
The ==
operator results in either true or false, so the index will be:
0
if false, if a
does not equal N
resulting in
1
if true, if a
equals N
resulting in
This is rather cryptic and could have been replaced with a simple if
.
For reference the C++14 standard(Lightness confirmed the draft matches the actual standard) with the closest draft being N3936 in section 2.14.5
String literals [lex.string] says (emphasis mine):
string literal has type “array of n const char”, where n is the
size of the string as defined below, and has static storage duration
(3.7).
and:
After any necessary concatenation, in translation phase 7 (2.2),
’’ is appended to every string literal so that programs that scan a string can find its end.
section 4.5
[conv.prom] says:
A prvalue of type bool can be converted to a prvalue of type int, with
false becoming zero and true becoming one.
Writing a null character to a text stream
The claim was made that writing a null character(
) to a text stream is undefined behavior.
As far as I can tell this is a reasonable conclusion, cout
is defined in terms of C stream, as we can see from 27.4.2
[narrow.stream.objects] which says:
The object cout controls output to a stream buffer associated with the object stdout, declared in
<cstdio> (27.9.2).
and the C11 draft standard in section 7.21.2
Streams says:
[...]Data read in from a text stream will necessarily compare equal to the data
that were earlier written out to that stream only if: the data consist only of printing
characters and the control characters horizontal tab and new-line;
and printing characters are covered in 7.4
Character handling <ctype.h>:
[...]the term control character
refers to a member of a locale-specific set of characters that are not printing
characters.199) All letters and digits are printing characters.
with footnote 199
saying:
In an implementation that uses the seven-bit US ASCII character set, the printing characters are those
whose values lie from 0x20 (space) through 0x7E (tilde); the control characters are those whose
values lie from 0 (NUL) through 0x1F (US), and the character 0x7F (DEL).
and finally we can see that the result of sending a null character is not specified and we can see this is undefined behavior from section 4
Conformance which says:
[...]Undefined behavior is otherwise
indicated in this International Standard by the words ‘‘undefined behavior’’ or by the
omission of any explicit definition of behavior.[...]
We can also look to the C99 rationale which says:
The set of characters required to be preserved in text stream I/O are those needed for writing C
programs; the intent is that the Standard should permit a C translator to be written in a maximally
portable fashion. Control characters such as backspace are not required for this purpose, so their
handling in text streams is not mandated.