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python - How do I extend, mimic, or emulate the range function?

I made a little generator function for character ranges:

>>> def crange(start, end):
...     for i in range(ord(start), ord(end)+1):
...             yield chr(i)
...

And then I can do this:

>>> print(*crange('a','e'))
a b c d e

Yay! But this doesn't work:

>>> crange('a','e')[::2]
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: 'generator' object is not subscriptable

And this works, but is O(n), unlike range's O(1):

>>> 'y' in crange('a','z')
True

That means it takes about 0.35 seconds to search for character number 109,999 out of the maximum of 110,000. 109999 in range(110000) is, of course, fast.

At that point, my first thought was to simply subclass range. Unfortunately:

>>> class A(range):
...     pass
...
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: type 'range' is not an acceptable base type

So I guess I would have to mimic it in some way that allows me to pass characters as arguments, works like range internally, and produces characters. Unfortunately, I'm not sure how to proceed. I tried a dir():

>>> print(*dir(range), sep='
')
__class__
__contains__
__delattr__
__dir__
__doc__
__eq__
__format__
__ge__
__getattribute__
__getitem__
__gt__
__hash__
__init__
__iter__
__le__
__len__
__lt__
__ne__
__new__
__reduce__
__reduce_ex__
__repr__
__reversed__
__setattr__
__sizeof__
__str__
__subclasshook__
count
index
start
step
stop

which lets me see what functions are in there, but I'm not sure what they're doing, or how range uses them. I looked for the source for range, but it's in C, and I don't know where to find its Python wrapper (it does have one, right?).

Where do I go from here, and should I even go there?

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1 Answer

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At that point, my first thought was to simply subclass range.

range was a function in Python2 and a "final" class in Python3 (more info here) - in both cases not something you can sub-class. You will need to create a class crange that extends from an object as the base type.

class crange(object):

And this works, but is O(n), unlike range's O(1)

In Python 3, there is a __contains__ method that you will define for your object.

For objects that don’t define __contains__(), the membership test first tries iteration via __iter__(), then the old sequence iteration protocol via __getitem__(), see this section in the language reference.

This allows Python to determine if the value is in your range without actually enumerating the range.

For a simple example, if your range is 1 to 1,000,000, it is trivial to determine whether 23546 is in that range (1 < 23546 < 1000000). Of course the actual implementation is a bit more complex and adds ability to handle step increments etc.

Regarding:

Yay! But this doesn't work: >>> crange('a','e')[::2]

In this case you need to define __getitem__ on your object. Here's an example of some of the methods required:

class crange(object):
    def __init__(self, start, end, step=1):
        # initialize your range object
        self.start = start
        self.end = end
        self.step = step

    def __iter__(self):
        # enable iteration over your object
        # (assume step size is 1)
        for i in range(ord(self.start), ord(self.end)+1):
            yield chr(i)

    def __getitem__(self, i):
        # enable accessing items in your range by index
        # also enable crange('a','e')[::2]
        # (assuming step size of 1)
        if isinstance( i, slice ):
            # implement slicing 
        else:
            return chr(ord(self.start) + i)

    def __contains__(self, char):
        # enable O(1) determination of whether a value is in your range
        # (assume step size is 1)
        return ord(self.start) <= ord(char) < ord(self.end)

    def __len__(self):
        # return length (assuming step size of 1)
        return ord(self.end) - ord(self.start)

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