Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
513 views
in Technique[技术] by (71.8m points)

swift3 - Converting Boolean value to Integer value in swift 3

I was converting from swift 2 to swift 3. I noticed that I cannot convert a boolean value to integer value in swift 3 : .

let p1 = ("a" == "a") //true

print(true)           //"true
"
print(p1)             //"true
"

Int(true)             //1

Int(p1)               //error

For example these syntaxes worked fine in swift 2. But in swift 3, print(p1) yields an error.

The error is error: cannot invoke initializer for type 'Int' with an argument list of type '((Bool))'

I understand why the errors are happening. Can anyone explain what is the reason for this safety and how to convert from Bool to Int in swift 3?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

You could use the ternary operator to convert a Bool to Int:

let result = condition ? 1 : 0

result will be 1 if condition is true, 0 is condition is false.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...