Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
733 views
in Technique[技术] by (71.8m points)

sorting - Difference between two lists using Bash

Ok, I have two related lists on my linux box in text files:

 /tmp/oldList
 /tmp/newList

I need to compare these lists to see what lines got added and what lines got removed. I then need to loop over these lines and perform actions on them based on whether they were added or removed.

How do I do this in bash?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Use the comm(1) command to compare the two files. They both need to be sorted, which you can do beforehand if they are large, or you can do it inline with bash process substitution.

comm can take a combination of the flags -1, -2 and -3 indicating which file to suppress lines from (unique to file 1, unique to file 2 or common to both).

To get the lines only in the old file:

comm -23 <(sort /tmp/oldList) <(sort /tmp/newList)

To get the lines only in the new file:

comm -13 <(sort /tmp/oldList) <(sort /tmp/newList)

You can feed that into a while read loop to process each line:

while read old ; do
    ...do stuff with $old
done < <(comm -23 <(sort /tmp/oldList) <(sort /tmp/newList))

and similarly for the new lines.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

2.1m questions

2.1m answers

60 comments

57.0k users

...