Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
136 views
in Technique[技术] by (71.8m points)

java - How to create my own filter with Spring MVC?

I use Spring MVC (4.0.1) as a backend for rest services and angularjs as frontend.

every request to my server backend has a http-header with a session id

I can read this header in my server backend with the following code:

@Autowired
protected HttpServletRequest request;
String xHeader=request.getHeader("X-Auth-Token"); //returns the sessionID from the header

Now I call this method getPermission(xHeader) it return only true or false. If the user exists in my DB it return true else false!

I want now create a filter with this behavior, that checks every request if the user have the permission to access my controllers! But if the method returns false it should send back a 401 error and not reach my controller!

How can I do this and create my own filter? I use only Java Config and no XML.

I think I must add the filter here:

public class WebInitializer extends AbstractAnnotationConfigDispatcherServletInitializer {
    @Override
    protected Filter[] getServletFilters() {
        MyOwnFilter=new MyOwnFilter();
        return new Filter[] {MyOwnFilter};
    }
}
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Alternative to Filters, you can use HandlerInterceptor.

public class SessionManager implements HandlerInterceptor{

    // This method is called before the controller
    @Override
    public boolean preHandle(HttpServletRequest request,
            HttpServletResponse response, Object handler) throws Exception {

        String xHeader = request.getHeader("X-Auth-Token");
        boolean permission = getPermission(xHeader);
        if(permission) {
            return true;
        }
        else {
            response.setStatus(HttpStatus.UNAUTHORIZED.value());
            return false;
            // Above code will send a 401 with no response body.
            // If you need a 401 view, do a redirect instead of
            // returning false.
            // response.sendRedirect("/401"); // assuming you have a handler mapping for 401

        }
        return false;
    }

    @Override
    public void postHandle(HttpServletRequest request,
            HttpServletResponse response, Object handler,
            ModelAndView modelAndView) throws Exception {

    }

    @Override
    public void afterCompletion(HttpServletRequest request,
            HttpServletResponse response, Object handler, Exception ex)
            throws Exception {

    }
}

And then add this interceptor to your webmvc config.

@EnableWebMvc
@Configuration
public class WebConfig extends WebMvcConfigurerAdapter {

    @Bean
    SessionManager getSessionManager() {
         return new SessionManager();
    }

    @Override
    public void addInterceptors(InterceptorRegistry registry) {
        registry.addInterceptor(getSessionManager())
        .addPathPatterns("/**")
        .excludePathPatterns("/resources/**", "/login");
     // assuming you put your serve your static files with /resources/ mapping
     // and the pre login page is served with /login mapping
    }

}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...