ajax - Enable Antiforgery Token with ASP.NET Core and JQuery

Question

I am using JQuery with ASP.NET Core 1.0.1 and I have the Ajax call:

$("#send-message").on("submit", function (event) {
  event.preventDefault();
  var $form = $(this);   
  $.ajax({
    url: "api/messages",
    data: JSON.stringify($form.serializeToJSON()),
    dataType: "json",
    headers: {
      Accept: "application/json",
      "Content-Type": "application/json"
    },
    type: "post"
  })
  .done(function (data, status, xhr) { })
  .fail(function (xhr, status, error) { });

To the ASP.NET Core action:

[HttpPost("messages")]
public async Task<IActionResult> Post([FromBody]MessagePostApiModelModel model) {
   // Send message
}

The form is in a shared view and it is the following:

<form id="send-question" method="post">
  <textarea name="content"></textarea>
  <button class="button" type="submit">Enviar</button>
</form>

When I submit the form I get the error:

Microsoft.AspNetCore.Antiforgery.AntiforgeryValidationException: The required antiforgery header value "RequestVerificationToken" is not present.

How can I enable ASP.NET Core's AntiForgeryToken with JQuery Ajax calls?

UPDATE

I need to add the following asp-controller and asp-action to the form:

<form asp-controller="QuestionApi" asp-action="Post" id="send-question" method="post">
</form>

This will generate the antiforgery token. And I needed to manually add the token to the headers of the JQuery call as follows:

  headers: {
    "Accept": "application/json",
    "Content-Type": "application/json",
    "RequestVerificationToken": $form.find("input[name='af_token']").val()
  },

Is there a better way to do this?

How do solve this when there is not form and I have only an A tag that when clicked makes the Ajax call? Can I generate a common antiforgery token on my page head to be used by all ajax calls from that page?

Answer 1

mode777's answer just needs a small addition to make this work (I tried it):

$(document).ajaxSend(function(e, xhr, options) {
    if (options.type.toUpperCase() == "POST") {
        var token = $form.find("input[name='af_token']").val();
        xhr.setRequestHeader("RequestVerificationToken", token);
    }
});

Actually, if you also submit using Ajax, you don't need to use a form at all. Put this in your _layout:

 <span class="AntiForge"> @Html.AntiForgeryToken() </span>

Then you pickup the token by adding this to your javascript:

$(document)
   .ajaxSend(function (event, jqxhr, settings) {
        if (settings.type.toUpperCase() != "POST") return;
        jqxhr.setRequestHeader('RequestVerificationToken', $(".AntiForge" + " input").val())
})

The @HtmlAntiForgeryToken generates a hidden input field with the antiforgery token, the same as when using a form. The code above finds it using the class selector to select the span, then gets the input field inside that to collect the token and add it as a header.