c# - Hiding a form and showing another when a button is clicked in a Windows Forms application

Question

I am doing an application a Windows Form application. At first, a certain form appears, and after the user hits the next button, this form should be hidden and another form is shown.

I tried to do it. I managed to hide the current form, but the next one won't show.

Here is my attempt:

This is the button's event handler

private void button1_Click_1(object sender, EventArgs e)
{
    if (richTextBox1.Text != null)
    {
        this.Visible=false;


    }
    else
        MessageBox.Show("Insert Attributes First !");
}

This is the main function:

static void Main()
{
    Application.EnableVisualStyles();
    Application.SetCompatibleTextRenderingDefault(false);
    Form2 form2 = new Form2();
    Form1 form1 = new Form1();
    form2.Hide();
    Application.Run(form1);
    while (true)
    {
        if (form1.Visible == false)
            form2.Show();
    }
}

Answer 1

The While statement will not execute until after form1 is closed - as it is outside the main message loop.

Remove it and change the first bit of code to:

private void button1_Click_1(object sender, EventArgs e)  
{  
    if (richTextBox1.Text != null)  
    {  
        this.Visible=false;
        Form2 form2 = new Form2();
        form2.show();
    }  
    else MessageBox.Show("Insert Attributes First !");  

}

This is not the best way to achieve what you are looking to do though. Instead consider the Wizard design pattern.

Alternatively you could implement a custom ApplicationContext that handles the lifetime of both forms. An example to implement a splash screen is here, which should set you on the right path.

http://www.codeproject.com/KB/cs/applicationcontextsplash.aspx?display=Print