java - Optionally getting field

Question

I have a class structure like this:

public class Foo {
    private FooB foob;

    public Optional<FooB> getFoob() {
        return Optional.ofNullable(foob);
    }
}

public class FooB {
    private int valA;

    public int getValA() {
        return valA;
    }
}

My objective is to call the get method for fooB and then check to see if it's present. If it is present then return the valA property, if it doesn't then just return null. So something like this:

Integer valA = foo.getFoob().ifPresent(getValA()).orElse(null);

Of course this isn't proper Java 8 optional syntax but that's my "psuedo code". Is there any way to achieve this in Java 8 with 1 line?

Answer 1

What you are describing is the method Optional.map:

Integer valA = foo.getFoob().map(foo -> foo.getValA()).orElse(null);

map lets you transform the value inside an Optional with a function if the value is present, and returns an empty the optional if the value in not present.

Note also that you can return null from the mapping function, in which case the result will be Optional.empty().