firebase realtime database - How to remove Optional from String Value Swift

Question

I'd like to use a String value without the optional extension. I parse this data from firebase using the following code:

Database.database().reference(withPath:
    "Locations").child("Cities").observe(.value, with: { (snapShot) in
        if snapShot.exists() {
            let array:NSArray = snapShot.children.allObjects as NSArray

            for child in array {
                let snap = child as! DataSnapshot

                let cityName = snap.key
                let cityNameString = "(cityName)"
                if snap.value is NSDictionary {
                    let data:NSDictionary = snap.value as! NSDictionary
                    let lat = data.value(forKey: "lat")
                    let lng = data.value(forKey: "lng")
                    let radius = data.value(forKey: "radius")
                    let latstring = "(lat)"
                    let lngstring = "(lng)" 
                    let radiusstring = "(radius)" 

                    let city = CityObject(name: cityNameString , lat: latstring , lng: lngstring, radius: radiusstring)
                    print("Value is", laststring)  
                    self.selectCity(cityObject: city)
                }                            

            }
        }
    })

after parsing this data i try to print e.g. the latstring and get following outpup:

Value is Optional(52.523553)

my CityObject looks like the following:

class CityObject{
var name: String?
var lat: String?
var lng: String?
var radius: String?

init(name: String?, lat: String?, lng: String?, radius: String?){
    self.name = name
    self.lat = lat
    self.lng = lng
    self.radius = radius
}

Answer 1

Waitting for answers