Yes.
Wrap the (global) xs:attribute
element in an xs:attributeGroup
element.
In the xs:element
element, refer to the xs:attributeGroup
element.
The name
attribute of the xs:attributeGroup
element can have the same value as the name
attribute of the xs:attribute
element.
Schema
<?xml version="1.0" encoding="utf-8"?>
<xs:schema targetNamespace="http://tempuri.org/XMLSchema.xsd"
elementFormDefault="qualified"
xmlns="http://tempuri.org/XMLSchema.xsd"
xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:attributeGroup name="sample-attribute">
<xs:attribute name="sample-attribute" type="xs:string" use="required"/>
</xs:attributeGroup>
<xs:element name="sample-element">
<xs:complexType>
<xs:attributeGroup ref="sample-attribute" />
</xs:complexType>
</xs:element>
</xs:schema>
Information not directly related to the question
This is not an extension to the answer above, nor an alternative answer, just related information that you might find helpful (it is not within the constraints of your question).
You could leave your original schema untouched, and explicitly qualify (add a namespace prefix to) the attribute name in the document instance, like this:
<?xml version="1.0" encoding="utf-8"?>
<t:sample-element
xmlns:t="http://tempuri.org/XMLSchema.xsd"
t:sample-attribute="test"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://tempuri.org/XMLSchema.xsd sample.xsd"/>
(Note the t:
namespace prefix on both the root element name and the attribute name.)
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