The manpage speaks of a message (singular) and multiple elements (plural):
For send()
and sendto()
, the message is found in buf
and has length
len
. For sendmsg()
, the message is pointed to by the elements of the
array msg.msg_iov
. The sendmsg()
call also allows sending ancillary
data (also known as control information).
For a stream socket, it wouldn't matter either way. Any data you send will just end up as one long stream of data on the other side.
For datagram or message sockets, I can see why a bit more clarity would be helpful. But it appears that you send just one datagram or message with a single sndmsg
call; not one per buffer element.
I actually went digging in the Linux source code out of curiosity and to get a better feeling about this answer. It looks like send
, and sendto
are just wrappers for sendmsg
in Linux, that build the struct msghdr
for you. And in fact, the UDP sendmsg
implementation makes room for one UDP header per sendmsg
call.
If performance is what you're worried about, it doesn't look like you'll benefit from sendmsg
if you pass in just a single iovec
. If you're concatenating buffers in user-space, though, this could potentially win you some.
It's a bit similar to writev
, with the added benefit that you can specify a destination address for use with connectionless sockets like UDP. You can also add ancillary data, if you're into that sort of thing. (Commonly used to send file descriptors across UNIX domain sockets.)
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