Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
487 views
in Technique[技术] by (71.8m points)

c - Finding common elements in two arrays of different size

I have a problem to find common elements in two arrays and that's of different size.

Take , Array A1 of size n and Array A2 of size m, and m != n

So far, I've tried to iterate lists one by one and copy elements to another list. If the element already contains mark it, but I know it's not a good solution.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Sort the arrays. Then iterate through them with two pointers, always advancing the one pointing to the smaller value. When they point to equal values, you have a common value. This will be O(n log n+m log m) where n and m are the sizes of the two lists. It's just like a merge in merge sort, but where you only produce output when the values being pointed to are equal.

def common_elements(a, b):
  a.sort()
  b.sort()
  i, j = 0, 0
  common = []
  while i < len(a) and j < len(b):
    if a[i] == b[j]:
      common.append(a[i])
      i += 1
      j += 1
    elif a[i] < b[j]:
      i += 1
    else:
      j += 1
  return common

print 'Common values:', ', '.join(map(str, common_elements([1, 2, 4, 8], [1, 4, 9])))

outputs

Common values: 1, 4

If the elements aren't comparable, throw the elements from one list into a hashmap and check the elements in the second list against the hashmap.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...