I am trying to parse an XML file from a URL by taking all "<Type>
" elements where is parameter type_id="4218"??
XML document:
<BSQCUBS Version="0.04" Date="Fri Dec 9 11:43:29 GMT 2011" MachineDate="Fri, 09 Dec 2011 11:43:29 +0000">
<Class class_id="385">
<Title>Football Matches</Title>
<Type type_id="4264" type_minbet="0.1" type_maxbet="2000.0">
...
</Type>
<Type type_id="5873" type_minbet="0" type_maxbet="0">
...
</Type>
<Type type_id="4725" type_minbet="0.1" type_maxbet="2000.0">
...
</Type>
<Type type_id="4218" type_minbet="0.1" type_maxbet="2000.0">
...
</Type>
<Type type_id="4221" type_minbet="0.1" type_maxbet="2000.0">
...
</Type>
<Type type_id="4218" type_minbet="0.1" type_maxbet="2000.0">
...
</Type>
<Type type_id="4299" type_minbet="0.1" type_maxbet="2000.0">
...
</Type>
</Class>
</BSQCUBS>
Here is my Java code:
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(new URL("http://cubs.bluesq.com/cubs/cubs.php?action=getpage&thepage=385.xml").openStream());
doc.getDocumentElement().normalize();
NodeList nodeList = doc.getElementsByTagName("Type");
System.out.println("ukupno:"+nodeList.getLength());
if (nodeList != null && nodeList.getLength() > 0) {
for (int j = 0; j < nodeList.getLength(); j++) {
Element el = (org.w3c.dom.Element) nodeList.item(j);
type_id = Integer.parseInt(el.getAttribute("type_id"));
System.out.println("type id:"+type_id);
}
}
This code gives me all elements, I don't want that, I want all elements where the attribute type_id = "4218"!
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