My question refers to whether or not the use of a ReentrantLock guarantees visibility of a field in the same respect that the synchronized keyword provides.
For example, in the following class A, the field sharedData does not need to be declared volatile as the synchronized keyword is used.
class A
{
private double sharedData;
public synchronized void method()
{
double temp = sharedData;
temp *= 2.5;
sharedData = temp + 1;
}
}
For next example using a ReentrantLock however, is the volatile keyword on the field necessary?
class B
{
private final ReentrantLock lock = new ReentrantLock();
private volatile double sharedData;
public void method()
{
lock.lock();
try
{
double temp = sharedData;
temp *= 2.5;
sharedData = temp + 1;
}
finally
{
lock.unlock();
}
}
}
I know that using the volatile keyword anyway will only likely impose a miniscule performance hit, but I would still like to code correctly.
See Question&Answers more detail:
os 与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…