string - C++, get the name of the function

Question

In C++, is there a way to get the function signature/name from it's pointer like this?

void test(float data) {}
cout << typeid(&test).name();

I want to use this data for logging.

Answer 1

C++, get the name of the calling function via a pointer:

Option 1: roll your own function name recorder

If you want to resolve a "pointer to a function" to a "function name", you will need to create your own lookup table of all available functions, then compare your pointer address to the key in the lookup table, and return the name.

An implementation described here: https://stackoverflow.com/a/8752173/445131

Option 2: Use __func__

GCC provides this magic variable that holds the name of the current function, as a string. It is part of the C99 standard:

#include <iostream>
using namespace std;
void foobar_function(){
    cout << "the name of this function is: " << __func__ << endl;
}
int main(int argc, char** argv) {
    cout << "the name of this function is: " << __func__ << endl;
    foobar_function();
    return 0;
}

Output:

the name of this function is: main
the name of this function is: foobar_function

Notes:

__FUNCTION__ is another name for __func__. Older versions of GCC recognize only this name. However, it is not standardized. If maximum portability is required, we recommend you use __func__, but provide a fallback definition with the preprocessor, to define it if it is undefined:

 #if __STDC_VERSION__ < 199901L
 # if __GNUC__ >= 2
 #  define __func__ __FUNCTION__
 # else
 #  define __func__ "<unknown>"
 # endif
 #endif

Source: http://gcc.gnu.org/onlinedocs/gcc/Function-Names.html