Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
253 views
in Technique[技术] by (71.8m points)

python - How to write a Django view for a POST request

I have written a very small example: a junit button which sends a POST request with a pair of values:

<!doctype html>

<html lang="en">
<head>
  <meta charset="utf-8" />
  <title>jQuery UI Button - Default functionality</title>
    <script src="{{STATIC_URL}}js/jquery-1.9.1.js"></script>
    <script src="{{STATIC_URL}}js/jquery-ui-1.10.3.custom.js"></script>
    <link rel="stylesheet" href="{{STATIC_URL}}css/jquery-ui-1.10.3.custom.css">

  <script>
  $(function() {
    $( "button" )
      .button()
      .click(function( event ) {
        var postdata = {
            'value1': 7,
            'value2': 5
        };
        $.post('', postdata); // POST request to the same view I am now
        window.alert("Hello world!"); // To know it is working
      });
  });
  </script>
</head>
<body>

<button>Submit</button>


</body>
</html>

So, the view is rendered when a GET request is sent to localhost:8000/button/, and when the button is pushed a POST request is also sent to localhost:8000/button/.

urls.py

from django.conf.urls import patterns, url

urlpatterns = patterns('',
    url(r'^button/$', 'helloworld.views.buttonExample'),
    )

views.py

def buttonExample(request):
    print 'RECEIVED REQUEST: ' + request.method
    if request.method == 'POST':
        print 'Hello'
    else: #GET
        return render(request, 'buttonExample.html')

When the GET request is done, the view is displayed correctly and I can also read at Django console the lines:

RECEIVED REQUEST: GET <---- This line is because of my print
[28/May/2013 05:20:30] "GET /button/ HTTP/1.1" 200 140898
[28/May/2013 05:20:30] "GET /static/js/jquery-1.9.1.js HTTP/1.1" 304 0
[28/May/2013 05:20:30] "GET /static/js/jquery-ui-1.10.3.custom.js HTTP/1.1" 304 0
[28/May/2013 05:20:30] "GET /static/css/jquery-ui-1.10.3.custom.css HTTP/1.1" 304 0
...

And when the button is pushed, I can see:

[28/May/2013 05:20:34] "POST /register/ HTTP/1.1" 403 142238

But "RECEIVED REQUEST: POST" is never printed. Neither is "Hello". It seems like the urls.py is not serving the view when a POST arrived, because in Firebug I can see that POST status is 403 FORBIDDEN.

This is probably a silly newbie mistake, but I don't know what am I missing. I have read the django book chapter about advanced URLConf and Views, and it looks like it should work just by checking request.method value.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

This is by design. Your POST data must contain csrfmiddlewaretoken value. You can get it from your cookies and then send it with POST requests. Details here. For your specific case, you can do this -

<script>
$(function () {
    function getCookie(name) {
        var cookieValue = null;
        if (document.cookie && document.cookie != '') {
            var cookies = document.cookie.split(';');
            for (var i = 0; i < cookies.length; i++) {
                var cookie = jQuery.trim(cookies[i]);
                // Does this cookie string begin with the name we want?
                if (cookie.substring(0, name.length + 1) == (name + '=')) {
                    cookieValue = decodeURIComponent(cookie.substring(name.length + 1));
                    break;
                }
            }
        }
        return cookieValue;
    }
    var csrftoken = getCookie('csrftoken');

    $("button")
        .button()
        .click(function (event) {
            var postdata = {
                'value1': 7,
                'value2': 5,
                'csrfmiddlewaretoken': csrftoken
            };
            $.post('', postdata); // POST request to the same view I am now
            window.alert("Hello world!"); // To know it is working
        });
});
</script>

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...