I don't see any mistake in your code. I have written a little program that prints out its args to the console
static void Main (string[] args)
{
foreach (string s in args)
Console.WriteLine(s);
Console.Read(); // Just to see the output
}
and then I have put it in C:, being the name of the app "PrintingArgs.exe", so I have written another one that executes the first:
Process p = new Process();
p.StartInfo.FileName = "C:\PrintingArgs.exe";
p.StartInfo.Arguments = "1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18";
p.Start();
this gives me the desired output of the list of numbers. The app that calls PrintingArgs exits as it reachs p.Start(), this could be avoided by using p.WaitForExit();
or just Console.Read();
.
Also I have used both p.UseShellExecute
and p.CreateNoWindow
. Only in the case that
p.UseShellExecute = false;
p.CreateNoWindow = true;
makes the PrintingArgs app not to show a window (even if I put only p.CreateNoWindow = true
it shows a window).
Now it comes to my mind that maybe your are passing the args in a wrong way and makes the other program to fail and close inmediately, or maybe you are not pointing to the right file. Check paths and names, in order to find any mistake you could omit.
Also, using
Process.Start(fileName, args);
does not uses the info you set up with StartInfo into your Process instance.
Hope this will help,
regards
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