By "non-empty", I mean in this question a string which contains at least one non-zero character.
For reference, here's the hashCode
implementation :
1493 public int hashCode() {
1494 int h = hash;
1495 if (h == 0) {
1496 int off = offset;
1497 char val[] = value;
1498 int len = count;
1499
1500 for (int i = 0; i < len; i++) {
1501 h = 31*h + val[off++];
1502 }
1503 hash = h;
1504 }
1505 return h;
1506 }
and the algorithm is specified in the documentation.
Before an integer overflow occurs, the answer is easy: it's no. But what I'd like to know is if, due to integer overflow, it's possible for a non-empty string to have a hashcode of zero? Can you construct one?
What I'm looking for would ideally be a mathematical demonstration (or a link to one) or a construction algorithm.
See Question&Answers more detail:
os 与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…