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c# - Pass current object type into base constructor call

How do I grab the Type of the inherited class and pass it into the base constructor of the class also inherited? See the code sample below:

// VeryBaseClass is in an external assembly
public abstract class VeryBaseClass
{
    public VeryBaseClass(string className, MyObject myObject)
    {

    }
}

// BaseClass and InheritedClass are in my assembly
public abstract class BaseClass : VeryBaseClass
{
    public BaseClass(MyObject myObject) :
        base(this.GetType().Name, myObject) // can't reference "this" (Type expected)
    {

    }
}

public class InheritedClass : BaseClass
{
    public InheritedClass(MyObject myObject)
    {

    }
}

The line base(typeof(this).Name, myObject) doesn't work because I can't reference this yet, as the object hasn't finished constructing and therefore doesn't exist.

Is it possible to grab the Type of the currently constructing object?

EDIT:

Corrected the sample as orsogufo suggested, but still doesn't work, as this is undefined.

EDIT 2:

Just to clarify, I want to end up with "InheritedClass" being passed into the VeryBaseClass(string className, MyObject myObject) constructor.

See Question&Answers more detail:os

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1 Answer

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by (71.8m points)

Ah Hah! I found a solution. You can do it with generics:

public abstract class VeryBaseClass
{
    public VeryBaseClass(string className, MyObject myObject)
    {
        this.ClassName = className;
    }

    public string ClassName{ get; set; }
}
public abstract class BaseClass<T> : VeryBaseClass
{
    public BaseClass(MyObject myObject)
        : base(typeof(T).Name, myObject)
    {
    }
}

public class InheritedClass : BaseClass<InheritedClass>
{
    public InheritedClass(MyObject myObject) 
        : base(myObject)
    {

    }
}

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