菜鸟教程小白 发表于 2022-12-13 06:05:43

ios - 可见区域外的目标注释方向


                                            <p><p>我想在屏幕的所有侧面显示方向图像。例如。如果目标的位置是用户位置的右侧并且在可见 map 区域之外,那么我想添加一个方向图像,如下图所示(绿色注释是用户位置,红色是目标的方向,超出屏幕范围):
<img src="/image/kOcls.png" alt="enter image description here"/> </p>

<p>执行此操作的标准方法是什么?</p></p>
                                    <br><hr><h1><strong>Best Answer-推荐答案</ strong></h1><br>
                                            <p><p>最简单的方法是在 map 上方的每个基点处放置四个“指针” View 。然后,随着用户移动 map (使用 <code>mapView:regionDidChangeAnimated:</code> 委托(delegate)方法)确定应该显示哪个指针。隐藏所有其他的;然后显示正确的。此外,对指针应用变换,以便如您所做的那样表示方位角。</p>

<p>以下是具有上述配置的 Storyboard 的屏幕截图:
<img src="/image/2LaJe.png" alt="storyboard"/> </p>

<p>这是一个示例实现(当然,代码不是最佳的。):</p>

<pre><code>//
//MapViewController.m
//AnimationTest
//
//Created by Scott Atkinson on 4/17/15.
//

#import &#34;MapViewController.h&#34;

@import MapKit;

typedef NS_ENUM(NSInteger, CardinalPoint) {
    North,
    South,
    East,
    West
};

@interface MapViewController () &lt;MKMapViewDelegate&gt;

@property (weak, nonatomic) IBOutlet MKMapView *mapView;

// Views that show cardinal points on the map (Only one should be shown at a time)
@property (weak, nonatomic) IBOutlet UIView *northPointerView;
@property (weak, nonatomic) IBOutlet UIView *eastPointerView;
@property (weak, nonatomic) IBOutlet UIView *westPointerView;
@property (weak, nonatomic) IBOutlet UIView *southPointerView;

// Location to show on the map
@property (strong, nonatomic) CLLocation * targetLocation;

@end

@implementation MapViewController

- (void)viewDidLoad {
    ;

    ;

    // Add the location to the map
    self.targetLocation = [ initWithLatitude:37.331898 longitude:-122.029824];
    MKPlacemark * placemark = [ initWithCoordinate:self.targetLocation.coordinate addressDictionary:nil];
    ;
}


// ******************** MKMapViewDelegate ********************
#pragma mark - MKMapViewDelegate

// As the map moves, update the cardinal pointer views
- (void) mapView:(MKMapView *)mapView regionDidChangeAnimated:(BOOL)animated {
    if( &amp;&amp; !) {
      // The user location is visible, but the target is not, so show a pointer
      double bearing = ;
      ;

    } else {
      // Hide the pointers
      ;
    }
}


// ******************** Coordinate Helpers ********************
#pragma mark - Coordinate Helpers

- (BOOL) isCurrentLocationVisible {
    return MKMapRectContainsPoint(self.mapView.visibleMapRect,
                                  MKMapPointForCoordinate(self.mapView.userLocation.coordinate));
}

- (BOOL) isTargetLocationVisible {
    return MKMapRectContainsPoint(self.mapView.visibleMapRect,
                                  MKMapPointForCoordinate(self.targetLocation.coordinate));
}

// From: http://stackoverflow.com/questions/3925942/cllocation-category-for-calculating-bearing-w-haversine-function
double DegreesToRadians(double degrees) {return degrees * M_PI / 180.0;};
double RadiansToDegrees(double radians) {return radians * 180.0/M_PI;};

/// Calculate the bearing between two points
-(double) bearingToLocation:(CLLocation *) destinationLocation fromLocation:(CLLocation *) fromLocation {

    double lat1 = DegreesToRadians(fromLocation.coordinate.latitude);
    double lon1 = DegreesToRadians(fromLocation.coordinate.longitude);

    double lat2 = DegreesToRadians(destinationLocation.coordinate.latitude);
    double lon2 = DegreesToRadians(destinationLocation.coordinate.longitude);

    double dLon = lon2 - lon1;

    double y = sin(dLon) * cos(lat2);
    double x = cos(lat1) * sin(lat2) - sin(lat1) * cos(lat2) * cos(dLon);
    double radiansBearing = atan2(y, x);

    if(radiansBearing &lt; 0.0)
      radiansBearing += 2*M_PI;

    return RadiansToDegrees(radiansBearing);
}

// ******************** Pointer View ********************
#pragma mark - Pointer View

- (void) hidePointerViews {
    self.northPointerView.hidden =
    self.southPointerView.hidden =
    self.eastPointerView.hidden =
    self.westPointerView.hidden = YES;
}

- (void) showCardinalPointDirection:(double) bearing {
    CardinalPoint point = ;

    // Determine which pointer should be shown based on the bearing
    UIView * activePointer;
    switch (point) {
      case North:
            activePointer = self.northPointerView;
            break;
      case South:
            activePointer = self.southPointerView;
            break;
      case East:
            activePointer = self.eastPointerView;
            break;
      case West:
            activePointer = self.westPointerView;
            break;
    }

    // Rotate the pointer to show the bearing
    activePointer.transform = CGAffineTransformMakeRotation(DegreesToRadians(bearing));

    // Hide all pointers except the pertinent one
    ;
    activePointer.hidden = NO;
}

/// Returns the cardinal point for a given bearing (in Degrees)
- (CardinalPoint) cardinalPointWithBearing:(double) bearing {
    if (bearing &gt; 45.0 &amp;&amp; bearing &lt;= 135.0) {
      return East;
    } else if (bearing &gt; 135.0 &amp;&amp; bearing &lt;= 225.0) {
      return South;
    } else if (bearing &gt; 225.0 &amp;&amp; bearing &lt;= 315.0) {
      return West;
    } else {
      return North;
    }
}
@end
</code></pre>

<p>此外,指针旋转基于<code>userLocation</code> 和<code>targetLocation</code> 之间的方位。感觉有点奇怪。根据其他点进行旋转可能更好。也许在那一刻可见区域的中心......</p></p>
                                   
                                                <p style="font-size: 20px;">关于ios - 可见区域外的目标注释方向,我们在Stack Overflow上找到一个类似的问题:
                                                        <a href="https://stackoverflow.com/questions/29271692/" rel="noreferrer noopener nofollow" style="color: red;">
                                                                https://stackoverflow.com/questions/29271692/
                                                        </a>
                                                </p>
                                       
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