IOS memcpy纹理到双数组
<p><p>您好,我使用以下函数将 sampleBuffer 绑定(bind)到 opengl 纹理,效果很好。</p>
<pre><code>void *imageData;
- (void)captureOutput:(AVCaptureOutput *)captureOutput didOutputSampleBuffer:(CMSampleBufferRef)sampleBuffer fromConnection:(AVCaptureConnection *)connection
{
UIImage * image = ;
if(imageData == NULL){
width = CGImageGetWidth(image.CGImage);
height = CGImageGetHeight(image.CGImage);
CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB();
imageData = malloc( height * width * 4 );
imgcontext = CGBitmapContextCreate(imageData, width, height, 8, 4 * width, colorSpace, kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big );
CGColorSpaceRelease( colorSpace );
}
CGContextClearRect( imgcontext, CGRectMake( 0, 0, width, height ) );
CGContextTranslateCTM( imgcontext, 0, height - height );
CGContextDrawImage( imgcontext, CGRectMake( 0, 0, width, height ), image.CGImage );
glBindTexture( GL_TEXTURE_2D, m_textureId );
glTexImage2D(GL_TEXTURE_2D, 0, GL_RGBA, width, height, 0, GL_RGBA, GL_UNSIGNED_BYTE, imageData);
}
</code></pre>
<p>我的问题是,我试图将 imageData 复制到双数组中,这样我就可以遍历所有像素以在不同的过程中进行一些处理。这是我正在使用的代码,它没有给我预期的结果。</p>
<pre><code> double data;
memcpy(data, imageData, width * height * 4);
for (int y = 0; y < height; y++)
{
for (int x = 0; x < width; x += 4)
{
double r = data[ y * width + x];
double g = data[ y * width + x + 1];
double b = data[ y * width + x + 2];
double a = data[ y * width + x + 3];
}
}
</code></pre>
<p>此代码在纹理绑定(bind)后直接调用,但 r、g、b 永远不会更改值。任何想法我可能做错了什么</p>
<p>干杯</p></p>
<br><hr><h1><strong>Best Answer-推荐答案</ strong></h1><br>
<p><p>看起来您正在分配 <code>imageData</code> 以将像素值存储为 32 位(4 字节)整数,但随后尝试将每个条目视为 <code>double</code> ( 8 个字节)。那是行不通的。</p>
<p>以下帖子可能会有所帮助:</p>
<p> <a href="https://stackoverflow.com/questions/448125/how-to-get-pixel-data-from-a-uiimage-cocoa-touch-or-cgimage-core-graphics" rel="noreferrer noopener nofollow">How to get pixel data from a UIImage (Cocoa Touch) or CGImage (Core Graphics)?</a> </p></p>
<p style="font-size: 20px;">关于IOS memcpy纹理到双数组,我们在Stack Overflow上找到一个类似的问题:
<a href="https://stackoverflow.com/questions/7943105/" rel="noreferrer noopener nofollow" style="color: red;">
https://stackoverflow.com/questions/7943105/
</a>
</p>
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