infer 这个关键字,整理记录一下,避免后面忘记了。有点难以理解呢。
infer
infer 是在 typescript 2.8中新增的关键字。
infer 可以在 extends 条件类型的字句中,在真实分支中引用此推断类型变量,推断待推断的类型。
例如:用infer推断函数的返回值类型
type ReturnType<T> = T extends (...args: any[]) => infer R ? R : any;
type fn = () => number
type fnReturnType = ReturnType<fn> // number
在这个例子中,
T extends U ? X : Y的形式为条件类型。
infer R代表待推断的返回值类型,如果T是一个函数(...args: any[]) => infer R,则返回函数的返回值R,否则返回any
案例:加深理解
反解 Promise
// promise 响应类型
type PromiseResType<T> = T extends Promise<infer R> ? R : T
// 验证
async function strPromise() {
return 'string promise'
}
interface Person {
name: string;
age: number;
}
async function personPromise() {
return {
name: 'p',
age: 12
} as Person
}
type StrPromise = ReturnType<typeof strPromise> // Promise<string>
// 反解
type StrPromiseRes = PromiseResType<StrPromise> // str
type PersonPromise = ReturnType<typeof personPromise> // Promise<Person>
// 反解
type PersonPromiseRes = PromiseResType<PersonPromise> // Person
反解函数入参类型
type Fn<A extends any[]> = (...args: A) => any
type FnArgs<T> = T extends Fn<infer A> ? A : any
function strFn (name: string) {
}
type StrFn = FnArgs<typeof strFn> // [string]
tuple 转 union ,如:[string, number] -> string | number
type ElementOf<T> = T extends Array<infer E> ? E : never
type TTuple = [string, number];
type ToUnion = ElementOf<ATuple>; // string | number
new 操作符
// 获取参数类型
type ConstructorParameters<T extends new (...args: any[]) => any> = T extends new (...args: infer P) => any ? P : never;
// 获取实例类型
type InstanceType<T extends new (...args: any[]) => any> = T extends new (...args: any[]) => infer R ? R : any;
class TestClass {
constructor(
public name: string,
public string: number
) {}
}
type Params = ConstructorParameters<typeof TestClass>; // [string, numbder]
type Instance = InstanceType<typeof TestClass>; // TestClass
react - reducer
// 定义
function useReducer<R extends Reducer<any, any>, I>(
reducer: R,
// ReducerState 推断类型
initializerArg: I & ReducerState<R>,
initializer: (arg: I & ReducerState<R>) => ReducerState<R>
): [ReducerState<R>, Dispatch<ReducerAction<R>>];
// infer推断
type ReducerState<R extends Reducer<any, any>> = R extends Reducer<infer S, any>
? S
: never;
// Reducer类型
type Reducer<S, A> = (prevState: S, action: A) => S;
// 使用 reducer
const reducer = (x: number) => x + 1;
const [state, dispatch] = useReducer(reducer, '');
// Argument of type "" is not assignable to parameter of type 'number'.
vue3 - ref
export interface Ref<T = any> {
[isRefSymbol]: true
value: T
}
export function ref<T>(value: T): T extends Ref ? T : Ref<UnwrapRef<T>>
export type UnwrapRef<T> = {
cRef: T extends ComputedRef<infer V> ? UnwrapRef<V> : T
ref: T extends Ref<infer V> ? UnwrapRef<V> : T
array: T
object: { [K in keyof T]: UnwrapRef<T[K]> }
}[T extends ComputedRef<any>
? 'cRef'
: T extends Array<any>
? 'array'
: T extends Ref | Function | CollectionTypes | BaseTypes
? 'ref' // bail out on types that shouldn't be unwrapped
: T extends object ? 'object' : 'ref']
// 使用
const count = ref({
foo: ref('1'),
bar: ref(2)
})
// 推断出
const count: Ref<{
foo: string;
bar: number;
}>
const count = ref(2) // Ref<number>
const count = ref(ref(2)) // Ref<number>
参考
理解TypeScript中的infer关键字
Vue3 跟着尤雨溪学 TypeScript 之 Ref 类型从零实现
巧用 TypeScript(五)---- infer
到此这篇关于深入理解typescript中的infer关键字的使用的文章就介绍到这了,更多相关typescript infer关键字内容请搜索极客世界以前的文章或继续浏览下面的相关文章希望大家以后多多支持极客世界! |
请发表评论