在线时间:8:00-16:00
迪恩网络APP
随时随地掌握行业动态
扫描二维码
关注迪恩网络微信公众号
本文主要为大家分析了Ajax技术组成原理,供大家参考,具体内容如下 1、Ajax 2、AJax的技术组成 3、Ajax核心原理 1)创建XMLHttpReuest对象 b)属性: readyState:服务器状态响应 responseText:服务器返回的数据(文本格式) 总结: 判断用户登录的HTML页面: <%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>登录</title> </head> <body> 用户名:<input type="text" name="username" id="username"><br> 密码:<input type="password" name="password" id="password"> <a href="javascript:chkUser();">登录</a> <div id="res"></div> </body> <script type="text/javascript"> var xhr; /** * 创建XMLHttpRequest对象 */ function createXMLHttpRequest(){ //1、创建XMLHttpRequest对象 if(window.XMLHttpRequest){ //非IE内核浏览器 xhr=new XMLHttpRequest(); }else{ //IE浏览器 try{ xhr=new ActiveXObject("Msxml2.XMLHTTP"); }catch(e){ //IE低版本 xhr=new ActiveXObject("Microsoft.XMLHTTP"); } } } /** * 发送请求,用来检查用户名、密码是否正确 */ function chkUser(){ //1、创建XMLHttpRequest createXMLHttpRequest(); //2、获得用户名、密码 var username=document.getElementById("username").value; var password=document.getElementById("password").value; //3、与服务器建立连接:open var url="login?username="+username+"&password="+password; //方式1:get提交 //xhr.open("GET",url,true); //方式2:post提交 var url2="login"; xhr.open("POST",url2,true); //4、设置回调函数,获得服务器响应的数据 xhr.onreadystatechange=function(){ /* readyState状态码: 0:未初始化 1:正在加载 2:加载完成 3:请求进行中 4:请求完成 */ if(xhr.readyState==4){ //status,200表示响应正常 if(xhr.status==200){ //alert("从服务器返回的值为:"+xhr.responseText); var res=xhr.responseText; if(res=='0'){ document.getElementById("res").innerHTML="登录成功"; }else{ document.getElementById("res").innerHTML="<font color='red'>登录失败</font>"; } }else{ alert("出现在了异常:"+xhr.response.Text); } } } //5、发送请求 //方式1:get方式 //xhr.send(null); //方式2:post方式: //Post提交需要设置http请求头 xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); xhr.send("username="+username+"&password="+password); } </script> </html> 服务端代码: package com.newer.login.web; import java.io.IOException; import java.io.PrintWriter; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.newer.login.bean.User; import com.newer.login.service.UserService; /** * Servlet implementation class LoginServlet */ public class LoginServlet extends HttpServlet { private static final long serialVersionUID = 1L; UserService userService = new UserService(); /** * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse * response) */ protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { doPost(request,response); } /** * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse * response) */ protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // 1、获得页面参数 String username = request.getParameter("username"); String password = request.getParameter("password"); System.out.println("获得请求的参数username:"+username); System.out.println("获得请求的参数password:"+password); // 2、封装User对象 User user = new User(); user.setUsername(username); user.setPassword(password); // 3、调用服务类,完成用户名、密码的校验 User u = userService.login(user); /* * 传统方式 if(u!=null){ //表示登录成功 request.setAttribute("user", user); * //跳转至首页... }else{ //登录失败,跳转登录页面 * * } */ // ajax响应 PrintWriter out = response.getWriter(); if (u != null) { //0成功,1失败 out.print(0); }else{ out.print(1); } out.close(); } } |
请发表评论