JSP中js传递和解析URL参数以及中文转码和解码问题

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1.传递参数：

 
var pmt = 'sensor='+ encodeURI(encodeURI(sensor))+'&device='+encodeURI(encodeURI(device))+'&instrument='; 
pmt += encodeURI(encodeURI(instrument))+'&n='+n+'&addDate='+addDate; 
top.location.href = 'jsp/print/diagnosticAnaPrint.jsp?'+pmt; 

2.接收和解析参数

复制代码代码如下:

 
//获取URL参数 
function GetRequest() { 
var url = location.search; //获取url中"?"符后的字串 
var theRequest = new Object(); 
if (url.indexOf("?") != -1) { 
var str = url.substr(1); 
strs = str.split("&"); 
for(var i = 0; i < strs.length; i ++) { 
theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]); 
} 
} 
return theRequest; 
} 

var sensor;//测点
sensor = decodeURI(decodeURI(Request['sensor']));
3.参考内容：
方法一：正则分析法

复制代码代码如下:

 
function getQueryString(name) { 
var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)", "i"); 
var r = window.location.search.substr(1).match(reg); 
if (r != null) return unescape(r[2]); return null; 
} 
这样调用： 
alert(GetQueryString("参数名1")); 
alert(GetQueryString("参数名2")); 
alert(GetQueryString("参数名3")); 

方法二：

复制代码代码如下:

 
<span style="font-size: 16px;"><Script language="javascript"> 
function GetRequest() { 
var url = location.search; //获取url中"?"符后的字串 
var theRequest = new Object(); 
if (url.indexOf("?") != -1) { 
var str = url.substr(1); 
strs = str.split("&"); 
for(var i = 0; i < strs.length; i ++) { 
theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]); 
} 
} 
return theRequest; 
} 
</Script></span> 
这样调用：  
<Script language="javascript"> 
var Request = new Object(); 
Request = GetRequest(); 
var 参数1,参数2,参数3,参数N; 
参数1 = Request['参数1']; 
参数2 = Request['参数2']; 
参数3 = Request['参数3']; 
参数N = Request['参数N']; 
</Script> 