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mysql服务启动,但是连接不上,如何解决? 登陆报错: root@localhost:~# mysql -u root -p Enter password: ERROR 2002 (HY000): Can't connect to local MySQL server through socket '/var/lib/mysql/mysql.sock' (2) root@localhost:~# service mysqld restart Shutting down MySQL.. [ OK ] Starting MySQL. [ OK ] root@localhost:~# mysql -u root -p Enter password: ERROR 2002 (HY000): Can't connect to local MySQL server through socket '/var/lib/mysql/mysql.sock' (2) 分析原因: 原因不详,知道了补上 解决方案一: root@localhost:~# find / -name mysql.sock /tmp/mysql.sock root@localhost:~# mysql -u root -p -S /tmp/mysql.sock Enter password: Welcome to the MySQL monitor. Commands end with ; or \g. Your MySQL connection id is 1 Server version: 5.6.15-log Source distribution Copyright (c) 2000, 2011, Oracle and/or its affiliates. All rights reserved. Oracle is a registered trademark of Oracle Corporation and/or its affiliates. Other names may be trademarks of their respective owners. Type 'help;' or '\h' for help. Type '\c' to clear the current input statement. mysql> 解决方案二: root@localhost:~# find / -name mysql.sock /tmp/mysql.sock root@localhost:~# vi /etc/my.cnf [mysqld] datadir=/var/lib/mysql socket=/var/lib/mysql/mysql.sock user=mysql # Default to using old password format for compatibility with mysql 3.x # clients (those using the mysqlclient10 compatibility package). old_passwords=1 # Disabling symbolic-links is recommended to prevent assorted security risks; # to do so, uncomment this line: # symbolic-links=0 # 加上下面的这段代码即可 [mysql] socket=/tmp/mysql.sock [mysqld_safe] log-error=/var/log/mysqld.log pid-file=/var/run/mysqld/mysqld.pid root@localhost:~# mysql -u root -p Enter password: Welcome to the MySQL monitor. Commands end with ; or \g. Your MySQL connection id is 3 Server version: 5.6.15-log Source distribution Copyright (c) 2000, 2011, Oracle and/or its affiliates. All rights reserved. Oracle is a registered trademark of Oracle Corporation and/or its affiliates. Other names may be trademarks of their respective owners. Type 'help;' or '\h' for help. Type '\c' to clear the current input statement. mysql> 以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持极客世界。 |
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