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一、查询某个字段重复 select * from User u where u.user_name in (select u.user_name from User u group by u.user_name having count(*) > 1) 二,删除表中某几个字段的重复 例:表中有条六条记录。 其中张三和王五 的记录有重复 id customer PhoneNo 001 张三 777777 002 李四 444444 003 王五 555555 004 张三 777777 005 张三 777777 006 王五 555555 如何写一个sql语句将TableA变成如下 001 张三 777777 002 李四 444444 003 王五 555555 测试环境 create table TableA ( id varchar(3),customer varchar(5),PhoneNo varchar(6)) insert into TableA select '001','张三','777777' union all select '002','李四','444444' union all select '003','王五','555555' union all select '004','张三','777777' union all select '005','张三','777777' union all select '006','王五','555555' 结果 delete TableA from TableA Twhere exists( select 1fromtablea where customer=T.customer and phoneno=T.phoneno andid < tt.id ) 总结 该方法适用于有一个字段为自增性,例如本例中的:id delete 表名 from 表名 as Twhere exists( select 1from表名 where 字段A=T.字段A and 字段B=T.字段B,(....) and自增列 < T.自增列 ) 三,查询并删除重复记录的SQL语句 查询及删除重复记录的SQL语句 select * from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) 2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录 delete from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1) 注:rowid为oracle自带不用该..... 3、查找表中多余的重复记录(多个字段) select * from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) 4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录 delete from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1) 5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录 select * from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1) (二) Select Name,Count(*) From A Group By Name Having Count(*) > 1 如果还查性别也相同大则如下: Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1 (三) 方法一 declare @max integer,@id integer declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; 1 open cur_rows fetch cur_rows into @id,@max while @@fetch_status=0 begin select @max = @max -1 set rowcount @max delete from 表名 where 主字段 = @id fetch cur_rows into @id,@max end close cur_rows set rowcount 0 方法二 select distinct * into #Tmp from tableName drop table tableName select * into tableName from #Tmp drop table #Tmp 发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。 2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下 select identity(int,1,1) as autoID, * into #Tmp from tableName select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID select * from #Tmp where autoID in(select autoID from #tmp2) 最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列) (四) select * from tablename where id in ( select id from tablename group by id having count(id) > 1 ) |
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