• 设为首页
  • 点击收藏
  • 手机版
    手机扫一扫访问
    迪恩网络手机版
  • 关注官方公众号
    微信扫一扫关注
    公众号

Oracle中检查外键是否有索引的SQL脚本分享

原作者: [db:作者] 来自: [db:来源] 收藏 邀请

复制代码 代码如下:

COLUMN COLUMNS format a30 word_wrapped
COLUMN tablename format a15 word_wrapped
COLUMN constraint_name format a15 word_wrapped
SELECT TABLE_NAME,
       CONSTRAINT_NAME,
       CNAME1 || NVL2(CNAME2, ',' || CNAME2, NULL) ||
       NVL2(CNAME3, ',' || CNAME3, NULL) ||
       NVL2(CNAME4, ',' || CNAME4, NULL) ||
       NVL2(CNAME5, ',' || CNAME5, NULL) ||
       NVL2(CNAME6, ',' || CNAME6, NULL) ||
       NVL2(CNAME7, ',' || CNAME7, NULL) ||
       NVL2(CNAME8, ',' || CNAME8, NULL) COLUMNS
  FROM (SELECT B.TABLE_NAME,
               B.CONSTRAINT_NAME,
               MAX(DECODE(POSITION, 1, COLUMN_NAME, NULL)) CNAME1,
               MAX(DECODE(POSITION, 2, COLUMN_NAME, NULL)) CNAME2,
               MAX(DECODE(POSITION, 3, COLUMN_NAME, NULL)) CNAME3,
               MAX(DECODE(POSITION, 4, COLUMN_NAME, NULL)) CNAME4,
               MAX(DECODE(POSITION, 5, COLUMN_NAME, NULL)) CNAME5,
               MAX(DECODE(POSITION, 6, COLUMN_NAME, NULL)) CNAME6,
               MAX(DECODE(POSITION, 7, COLUMN_NAME, NULL)) CNAME7,
               MAX(DECODE(POSITION, 8, COLUMN_NAME, NULL)) CNAME8,
               COUNT(*) COL_CNT
          FROM (SELECT SUBSTR(TABLE_NAME, 1, 30) TABLE_NAME,
                       SUBSTR(CONSTRAINT_NAME, 1, 30) CONSTRAINT_NAME,
                       SUBSTR(COLUMN_NAME, 1, 30) COLUMN_NAME,
                       POSITION
                  FROM USER_CONS_COLUMNS) A,
               USER_CONSTRAINTS B
         WHERE A.CONSTRAINT_NAME = B.CONSTRAINT_NAME
           AND B.CONSTRAINT_TYPE = 'R'
         GROUP BY B.TABLE_NAME, B.CONSTRAINT_NAME) CONS
 WHERE COL_CNT > ALL
 (SELECT COUNT(*)
          FROM USER_IND_COLUMNS I
         WHERE I.TABLE_NAME = CONS.TABLE_NAME
           AND I.COLUMN_NAME IN (CNAME1, CNAME2, CNAME3, CNAME4, CNAME5,
                CNAME6, CNAME7, CNAME8)
           AND I.COLUMN_POSITION <= CONS.COL_CNT
         GROUP BY I.INDEX_NAME)
/

在上面的基础上修改了一下,可以检查所有的用户。
复制代码 代码如下:

SET linesize 400;
COLUMN OWNER format a10 word_wrapped
COLUMN COLUMNS format a30 word_wrapped
COLUMN TABLE_NAME format a15 word_wrapped
COLUMN CONSTRAINT_NAME format a40 word_wrapped
SELECT OWNER,
     TABLE_NAME,
       CONSTRAINT_NAME,
       CNAME1 || NVL2(CNAME2, ',' || CNAME2, NULL) ||
       NVL2(CNAME3, ',' || CNAME3, NULL) ||
       NVL2(CNAME4, ',' || CNAME4, NULL) ||
       NVL2(CNAME5, ',' || CNAME5, NULL) ||
       NVL2(CNAME6, ',' || CNAME6, NULL) ||
       NVL2(CNAME7, ',' || CNAME7, NULL) ||
       NVL2(CNAME8, ',' || CNAME8, NULL) COLUMNS
  FROM (SELECT B.OWNER,B.TABLE_NAME,
               B.CONSTRAINT_NAME,
               MAX(DECODE(POSITION, 1, COLUMN_NAME, NULL)) CNAME1,
               MAX(DECODE(POSITION, 2, COLUMN_NAME, NULL)) CNAME2,
               MAX(DECODE(POSITION, 3, COLUMN_NAME, NULL)) CNAME3,
               MAX(DECODE(POSITION, 4, COLUMN_NAME, NULL)) CNAME4,
               MAX(DECODE(POSITION, 5, COLUMN_NAME, NULL)) CNAME5,
               MAX(DECODE(POSITION, 6, COLUMN_NAME, NULL)) CNAME6,
               MAX(DECODE(POSITION, 7, COLUMN_NAME, NULL)) CNAME7,
               MAX(DECODE(POSITION, 8, COLUMN_NAME, NULL)) CNAME8,
               COUNT(*) COL_CNT
          FROM (SELECT SUBSTR(TABLE_NAME, 1, 30) TABLE_NAME,
                       SUBSTR(CONSTRAINT_NAME, 1, 30) CONSTRAINT_NAME,
                       SUBSTR(COLUMN_NAME, 1, 30) COLUMN_NAME,
                       POSITION
                  FROM DBA_CONS_COLUMNS WHERE OWNER NOT IN ('SYS','SYSTEM','SYSMAN','HR','OE','EXFSYS','DBSNMP','MDSYS','OLAPSYS','SCOTT','EXFSYS','SH','PM','CTXSYS')) A,
               DBA_CONSTRAINTS B
         WHERE A.CONSTRAINT_NAME = B.CONSTRAINT_NAME
           AND B.CONSTRAINT_TYPE = 'R'
         GROUP BY B.OWNER,B.TABLE_NAME, B.CONSTRAINT_NAME) CONS
 WHERE COL_CNT > ALL
 (SELECT COUNT(*)
          FROM DBA_IND_COLUMNS I
         WHERE I.TABLE_NAME = CONS.TABLE_NAME AND I.TABLE_OWNER=CONS.OWNER
           AND I.COLUMN_NAME IN (CNAME1, CNAME2, CNAME3, CNAME4, CNAME5,
                CNAME6, CNAME7, CNAME8)
           AND I.COLUMN_POSITION <= CONS.COL_CNT
         GROUP BY I.INDEX_NAME)
/


鲜花

握手

雷人

路过

鸡蛋
该文章已有0人参与评论

请发表评论

全部评论

专题导读
上一篇:
Mongodb自增id实现方法发布时间:2022-02-08
下一篇:
MySQL索引失效的几种情况汇总发布时间:2022-02-08
热门推荐
热门话题
阅读排行榜

扫描微信二维码

查看手机版网站

随时了解更新最新资讯

139-2527-9053

在线客服(服务时间 9:00~18:00)

在线QQ客服
地址:深圳市南山区西丽大学城创智工业园
电邮:jeky_zhao#qq.com
移动电话:139-2527-9053

Powered by 互联科技 X3.4© 2001-2213 极客世界.|Sitemap