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前言 Redis作为缓存使用时,一些场景下要考虑内存的空间消耗问题。Redis会删除过期键以释放空间,过期键的删除策略有两种:
另外,Redis也可以开启LRU功能来自动淘汰一些键值对。 LRU算法 当需要从缓存中淘汰数据时,我们希望能淘汰那些将来不可能再被使用的数据,保留那些将来还会频繁访问的数据,但最大的问题是缓存并不能预言未来。一个解决方法就是通过LRU进行预测:最近被频繁访问的数据将来被访问的可能性也越大。缓存中的数据一般会有这样的访问分布:一部分数据拥有绝大部分的访问量。当访问模式很少改变时,可以记录每个数据的最后一次访问时间,拥有最少空闲时间的数据可以被认为将来最有可能被访问到。 举例如下的访问模式,A每5s访问一次,B每2s访问一次,C与D每10s访问一次,|代表计算空闲时间的截止点:
可以看到,LRU对于A、B、C工作的很好,完美预测了将来被访问到的概率B>A>C,但对于D却预测了最少的空闲时间。 但是,总体来说,LRU算法已经是一个性能足够好的算法了 LRU配置参数 Redis配置中和LRU有关的有三个:
淘汰策略 淘汰策略即maxmemory_policy的赋值有以下几种:
volatile-lru, volatile-random和volatile-ttl这三个淘汰策略使用的不是全量数据,有可能无法淘汰出足够的内存空间。在没有过期键或者没有设置超时属性的键的情况下,这三种策略和noeviction差不多。 一般的经验规则:
volatile-lru 和 volatile-random策略,当你想要使用单一的Redis实例来同时实现缓存淘汰和持久化一些经常使用的键集合时很有用。未设置过期时间的键进行持久化保存,设置了过期时间的键参与缓存淘汰。不过一般运行两个实例是解决这个问题的更好方法。 为键设置过期时间也是需要消耗内存的,所以使用allkeys-lru这种策略更加节省空间,因为这种策略下可以不为键设置过期时间。 近似LRU算法 我们知道,LRU算法需要一个双向链表来记录数据的最近被访问顺序,但是出于节省内存的考虑,Redis的LRU算法并非完整的实现。Redis并不会选择最久未被访问的键进行回收,相反它会尝试运行一个近似LRU的算法,通过对少量键进行取样,然后回收其中的最久未被访问的键。通过调整每次回收时的采样数量maxmemory-samples,可以实现调整算法的精度。 根据Redis作者的说法,每个Redis Object可以挤出24 bits的空间,但24 bits是不够存储两个指针的,而存储一个低位时间戳是足够的,Redis Object以秒为单位存储了对象新建或者更新时的unix time,也就是LRU clock,24 bits数据要溢出的话需要194天,而缓存的数据更新非常频繁,已经足够了。 Redis的键空间是放在一个哈希表中的,要从所有的键中选出一个最久未被访问的键,需要另外一个数据结构存储这些源信息,这显然不划算。最初,Redis只是随机的选3个key,然后从中淘汰,后来算法改进到了N个key的策略,默认是5个。 Redis3.0之后又改善了算法的性能,会提供一个待淘汰候选key的pool,里面默认有16个key,按照空闲时间排好序。更新时从Redis键空间随机选择N个key,分别计算它们的空闲时间idle,key只会在pool不满或者空闲时间大于pool里最小的时,才会进入pool,然后从pool中选择空闲时间最大的key淘汰掉。 真实LRU算法与近似LRU的算法可以通过下面的图像对比: 浅灰色带是已经被淘汰的对象,灰色带是没有被淘汰的对象,绿色带是新添加的对象。可以看出,maxmemory-samples值为5时Redis 3.0效果比Redis 2.8要好。使用10个采样大小的Redis 3.0的近似LRU算法已经非常接近理论的性能了。 数据访问模式非常接近幂次分布时,也就是大部分的访问集中于部分键时,LRU近似算法会处理得很好。 在模拟实验的过程中,我们发现如果使用幂次分布的访问模式,真实LRU算法和近似LRU算法几乎没有差别。 LRU源码分析 Redis中的键与值都是redisObject对象: typedef struct redisObject { unsigned type:4; unsigned encoding:4; unsigned lru:LRU_BITS; /* LRU time (relative to global lru_clock) or * LFU data (least significant 8 bits frequency * and most significant 16 bits access time). */ int refcount; void *ptr; } robj; unsigned的低24 bits的lru记录了redisObj的LRU time。 Redis命令访问缓存的数据时,均会调用函数lookupKey: robj *lookupKey(redisDb *db, robj *key, int flags) { dictEntry *de = dictFind(db->dict,key->ptr); if (de) { robj *val = dictGetVal(de); /* Update the access time for the ageing algorithm. * Don't do it if we have a saving child, as this will trigger * a copy on write madness. */ if (server.rdb_child_pid == -1 && server.aof_child_pid == -1 && !(flags & LOOKUP_NOTOUCH)) { if (server.maxmemory_policy & MAXMEMORY_FLAG_LFU) { updateLFU(val); } else { val->lru = LRU_CLOCK(); } } return val; } else { return NULL; } } 该函数在策略为LRU(非LFU)时会更新对象的lru值, 设置为LRU_CLOCK()值: /* Return the LRU clock, based on the clock resolution. This is a time * in a reduced-bits format that can be used to set and check the * object->lru field of redisObject structures. */ unsigned int getLRUClock(void) { return (mstime()/LRU_CLOCK_RESOLUTION) & LRU_CLOCK_MAX; } /* This function is used to obtain the current LRU clock. * If the current resolution is lower than the frequency we refresh the * LRU clock (as it should be in production servers) we return the * precomputed value, otherwise we need to resort to a system call. */ unsigned int LRU_CLOCK(void) { unsigned int lruclock; if (1000/server.hz <= LRU_CLOCK_RESOLUTION) { atomicGet(server.lruclock,lruclock); } else { lruclock = getLRUClock(); } return lruclock; } LRU_CLOCK()取决于LRU_CLOCK_RESOLUTION(默认值1000),LRU_CLOCK_RESOLUTION代表了LRU算法的精度,即一个LRU的单位是多长。server.hz代表服务器刷新的频率,如果服务器的时间更新精度值比LRU的精度值要小,LRU_CLOCK()直接使用服务器的时间,减小开销。 Redis处理命令的入口是processCommand: int processCommand(client *c) { /* Handle the maxmemory directive. * * Note that we do not want to reclaim memory if we are here re-entering * the event loop since there is a busy Lua script running in timeout * condition, to avoid mixing the propagation of scripts with the * propagation of DELs due to eviction. */ if (server.maxmemory && !server.lua_timedout) { int out_of_memory = freeMemoryIfNeededAndSafe() == C_ERR; /* freeMemoryIfNeeded may flush slave output buffers. This may result * into a slave, that may be the active client, to be freed. */ if (server.current_client == NULL) return C_ERR; /* It was impossible to free enough memory, and the command the client * is trying to execute is denied during OOM conditions or the client * is in MULTI/EXEC context? Error. */ if (out_of_memory && (c->cmd->flags & CMD_DENYOOM || (c->flags & CLIENT_MULTI && c->cmd->proc != execCommand))) { flagTransaction(c); addReply(c, shared.oomerr); return C_OK; } } } 只列出了释放内存空间的部分,freeMemoryIfNeededAndSafe为释放内存的函数: int freeMemoryIfNeeded(void) { /* By default replicas should ignore maxmemory * and just be masters exact copies. */ if (server.masterhost && server.repl_slave_ignore_maxmemory) return C_OK; size_t mem_reported, mem_tofree, mem_freed; mstime_t latency, eviction_latency; long long delta; int slaves = listLength(server.slaves); /* When clients are paused the dataset should be static not just from the * POV of clients not being able to write, but also from the POV of * expires and evictions of keys not being performed. */ if (clientsArePaused()) return C_OK; if (getMaxmemoryState(&mem_reported,NULL,&mem_tofree,NULL) == C_OK) return C_OK; mem_freed = 0; if (server.maxmemory_policy == MAXMEMORY_NO_EVICTION) goto cant_free; /* We need to free memory, but policy forbids. */ latencyStartMonitor(latency); while (mem_freed < mem_tofree) { int j, k, i, keys_freed = 0; static unsigned int next_db = 0; sds bestkey = NULL; int bestdbid; redisDb *db; dict *dict; dictEntry *de; if (server.maxmemory_policy & (MAXMEMORY_FLAG_LRU|MAXMEMORY_FLAG_LFU) || server.maxmemory_policy == MAXMEMORY_VOLATILE_TTL) { struct evictionPoolEntry *pool = EvictionPoolLRU; while(bestkey == NULL) { unsigned long total_keys = 0, keys; /* We don't want to make local-db choices when expiring keys, * so to start populate the eviction pool sampling keys from * every DB. */ for (i = 0; i < server.dbnum; i++) { db = server.db+i; dict = (server.maxmemory_policy & MAXMEMORY_FLAG_ALLKEYS) ? db->dict : db->expires; if ((keys = dictSize(dict)) != 0) { evictionPoolPopulate(i, dict, db->dict, pool); total_keys += keys; } } if (!total_keys) break; /* No keys to evict. */ /* Go backward from best to worst element to evict. */ for (k = EVPOOL_SIZE-1; k >= 0; k--) { if (pool[k].key == NULL) continue; bestdbid = pool[k].dbid; if (server.maxmemory_policy & MAXMEMORY_FLAG_ALLKEYS) { de = dictFind(server.db[pool[k].dbid].dict, pool[k].key); } else { de = dictFind(server.db[pool[k].dbid].expires, pool[k].key); } /* Remove the entry from the pool. */ if (pool[k].key != pool[k].cached) sdsfree(pool[k].key); pool[k].key = NULL; pool[k].idle = 0; /* If the key exists, is our pick. Otherwise it is * a ghost and we need to try the next element. */ if (de) { bestkey = dictGetKey(de); break; } else { /* Ghost... Iterate again. */ } } } } /* volatile-random and allkeys-random policy */ else if (server.maxmemory_policy == MAXMEMORY_ALLKEYS_RANDOM || server.maxmemory_policy == MAXMEMORY_VOLATILE_RANDOM) { /* When evicting a random key, we try to evict a key for * each DB, so we use the static 'next_db' variable to * incrementally visit all DBs. */ for (i = 0; i < server.dbnum; i++) { j = (++next_db) % server.dbnum; db = server.db+j; dict = (server.maxmemory_policy == MAXMEMORY_ALLKEYS_RANDOM) ? db->dict : db->expires; if (dictSize(dict) != 0) { de = dictGetRandomKey(dict); bestkey = dictGetKey(de); bestdbid = j; break; } } } /* Finally remove the selected key. */ if (bestkey) { db = server.db+bestdbid; robj *keyobj = createStringObject(bestkey,sdslen(bestkey)); propagateExpire(db,keyobj,server.lazyfree_lazy_eviction); /* We compute the amount of memory freed by db*Delete() alone. * It is possible that actually the memory needed to propagate * the DEL in AOF and replication link is greater than the one * we are freeing removing the key, but we can't account for * that otherwise we would never exit the loop. * * AOF and Output buffer memory will be freed eventually so * we only care about memory used by the key space. */ delta = (long long) zmalloc_used_memory(); latencyStartMonitor(eviction_latency); if (server.lazyfree_lazy_eviction) dbAsyncDelete(db,keyobj); else dbSyncDelete(db,keyobj); latencyEndMonitor(eviction_latency); latencyAddSampleIfNeeded("eviction-del",eviction_latency); latencyRemoveNestedEvent(latency,eviction_latency); delta -= (long long) zmalloc_used_memory(); mem_freed += delta; server.stat_evictedkeys++; notifyKeyspaceEvent(NOTIFY_EVICTED, "evicted", keyobj, db->id); decrRefCount(keyobj); keys_freed++; /* When the memory to free starts to be big enough, we may * start spending so much time here that is impossible to * deliver data to the slaves fast enough, so we force the * transmission here inside the loop. */ if (slaves) flushSlavesOutputBuffers(); /* Normally our stop condition is the ability to release * a fixed, pre-computed amount of memory. However when we * are deleting objects in another thread, it's better to * check, from time to time, if we already reached our target * memory, since the "mem_freed" amount is computed only * across the dbAsyncDelete() call, while the thread can * release the memory all the time. */ if (server.lazyfree_lazy_eviction && !(keys_freed % 16)) { if (getMaxmemoryState(NULL,NULL,NULL,NULL) == C_OK) { /* Let's satisfy our stop condition. */ mem_freed = mem_tofree; } } } if (!keys_freed) { latencyEndMonitor(latency); latencyAddSampleIfNeeded("eviction-cycle",latency); goto cant_free; /* nothing to free... */ } } latencyEndMonitor(latency); latencyAddSampleIfNeeded("eviction-cycle",latency); return C_OK; cant_free: /* We are here if we are not able to reclaim memory. There is only one * last thing we can try: check if the lazyfree thread has jobs in queue * and wait... */ while(bioPendingJobsOfType(BIO_LAZY_FREE)) { if (((mem_reported - zmalloc_used_memory()) + mem_freed) >= mem_tofree) break; usleep(1000); } return C_ERR; } /* This is a wrapper for freeMemoryIfNeeded() that only really calls the * function if right now there are the conditions to do so safely: * * - There must be no script in timeout condition. * - Nor we are loading data right now. * */ int freeMemoryIfNeededAndSafe(void) { if (server.lua_timedout || server.loading) return C_OK; return freeMemoryIfNeeded(); } 几种淘汰策略maxmemory_policy就是在这个函数里面实现的。 当采用LRU时,可以看到,从0号数据库开始(默认16个),根据不同的策略,选择redisDb的dict(全部键)或者expires(有过期时间的键),用来更新候选键池子pool,pool更新策略是evictionPoolPopulate: void evictionPoolPopulate(int dbid, dict *sampledict, dict *keydict, struct evictionPoolEntry *pool) { int j, k, count; dictEntry *samples[server.maxmemory_samples]; count = dictGetSomeKeys(sampledict,samples,server.maxmemory_samples); for (j = 0; j < count; j++) { unsigned long long idle; sds key; robj *o; dictEntry *de; de = samples[j]; key = dictGetKey(de); /* If the dictionary we are sampling from is not the main * dictionary (but the expires one) we need to lookup the key * again in the key dictionary to obtain the value object. */ if (server.maxmemory_policy != MAXMEMORY_VOLATILE_TTL) { if (sampledict != keydict) de = dictFind(keydict, key); o = dictGetVal(de); } /* Calculate the idle time according to the policy. This is called * idle just because the code initially handled LRU, but is in fact * just a score where an higher score means better candidate. */ if (server.maxmemory_policy & MAXMEMORY_FLAG_LRU) { idle = estimateObjectIdleTime(o); } else if (server.maxmemory_policy & MAXMEMORY_FLAG_LFU) { /* When we use an LRU policy, we sort the keys by idle time * so that we expire keys starting from greater idle time. * However when the policy is an LFU one, we have a frequency * estimation, and we want to evict keys with lower frequency * first. So inside the pool we put objects using the inverted * frequency subtracting the actual frequency to the maximum * frequency of 255. */ idle = 255-LFUDecrAndReturn(o); } else if (server.maxmemory_policy == MAXMEMORY_VOLATILE_TTL) { /* In this case the sooner the expire the better. */ idle = ULLONG_MAX - (long)dictGetVal(de); } else { serverPanic("Unknown eviction policy in evictionPoolPopulate()"); } /* Insert the element inside the pool. * First, find the first empty bucket or the first populated * bucket that has an idle time smaller than our idle time. */ k = 0; while (k < EVPOOL_SIZE && pool[k].key && pool[k].idle < idle) k++; if (k == 0 && pool[EVPOOL_SIZE-1].key != NULL) { /* Can't insert if the element is < the worst element we have * and there are no empty buckets. */ continue; } else if (k < EVPOOL_SIZE && pool[k].key == NULL) { /* Inserting into empty position. No setup needed before insert. */ } else { /* Inserting in the middle. Now k points to the first element * greater than the element to insert. */ if (pool[EVPOOL_SIZE-1].key == NULL) { /* Free space on the right? Insert at k shifting * all the elements from k to end to the right. */ /* Save SDS before overwriting. */ sds cached = pool[EVPOOL_SIZE-1].cached; memmove(pool+k+1,pool+k, sizeof(pool[0])*(EVPOOL_SIZE-k-1)); pool[k].cached = cached; } else { /* No free space on right? Insert at k-1 */ k--; /* Shift all elements on the left of k (included) to the * left, so we discard the element with smaller idle time. */ sds cached = pool[0].cached; /* Save SDS before overwriting. */ if (pool[0].key != pool[0].cached) sdsfree(pool[0].key); memmove(pool,pool+1,sizeof(pool[0])*k); pool[k].cached = cached; } } /* Try to reuse the cached SDS string allocated in the pool entry, * because allocating and deallocating this object is costly * (according to the profiler, not my fantasy. Remember: * premature optimizbla bla bla bla. */ int klen = sdslen(key); if (klen > EVPOOL_CACHED_SDS_SIZE) { pool[k].key = sdsdup(key); } else { memcpy(pool[k].cached,key,klen+1); sdssetlen(pool[k].cached,klen); pool[k].key = pool[k].cached; } pool[k].idle = idle; pool[k].dbid = dbid; } } Redis随机选择maxmemory_samples数量的key,然后计算这些key的空闲时间idle time,当满足条件时(比pool中的某些键的空闲时间还大)就可以进pool。pool更新之后,就淘汰pool中空闲时间最大的键。 estimateObjectIdleTime用来计算Redis对象的空闲时间: /* Given an object returns the min number of milliseconds the object was never * requested, using an approximated LRU algorithm. */ unsigned long long estimateObjectIdleTime(robj *o) { unsigned long long lruclock = LRU_CLOCK(); if (lruclock >= o->lru) { return (lruclock - o->lru) * LRU_CLOCK_RESOLUTION; } else { return (lruclock + (LRU_CLOCK_MAX - o->lru)) * LRU_CLOCK_RESOLUTION; } } 空闲时间基本就是就是对象的lru和全局的LRU_CLOCK()的差值乘以精度LRU_CLOCK_RESOLUTION,将秒转化为了毫秒。 参考链接 总结 以上就是这篇文章的全部内容了,希望本文的内容对大家的学习或者工作具有一定的参考学习价值,谢谢大家对极客世界的支持。 |
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