本文整理汇总了VB.NET中System.Convert.ToInt16方法的典型用法代码示例。如果您正苦于以下问题:VB.NET Convert.ToInt16方法的具体用法?VB.NET Convert.ToInt16怎么用?VB.NET Convert.ToInt16使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类System.Convert 的用法示例。
在下文中一共展示了Convert.ToInt16方法的18个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的VB.NET代码示例。
示例1: numbers
Dim numbers() As SByte = { SByte.MinValue, -1, 0, 10, SByte.MaxValue }
Dim result As Short
For Each number As SByte In numbers
result = Convert.ToInt16(number)
Console.WriteLine("Converted the {0} value {1} to the {2} value {3}.", _
number.GetType().Name, number, _
result.GetType().Name, result)
Next
开发者ID:VB.NET开发者,项目名称:System,代码行数:9,代码来源:Convert.ToInt16 输出:
Converted the SByte value -128 to the Int16 value -128.
Converted the SByte value -1 to the Int16 value -1.
Converted the SByte value 0 to the Int16 value 0.
Converted the SByte value 10 to the Int16 value 10.
Converted the SByte value 127 to the Int16 value 127.
示例2: ToInt16ProviderDemo
' Example of the Convert.ToInt16( String ) and
' Convert.ToInt16( String, IFormatProvider ) methods.
Imports System.Globalization
Module ToInt16ProviderDemo
Dim format As String = "{0,-20}{1,-20}{2}"
' Get the exception type name; remove the namespace prefix.
Function GetExceptionType( ex As Exception ) As String
Dim exceptionType As String = ex.GetType( ).ToString( )
Return exceptionType.Substring( _
exceptionType.LastIndexOf( "."c ) + 1 )
End Function
Sub ConvertToInt16( numericStr As String, _
provider As IFormatProvider )
Dim defaultValue As Object
Dim providerValue As Object
' Convert numericStr to Int16 without a format provider.
Try
defaultValue = Convert.ToInt16( numericStr )
Catch ex As Exception
defaultValue = GetExceptionType( ex )
End Try
' Convert numericStr to Int16 with a format provider.
Try
providerValue = Convert.ToInt16( numericStr, provider )
Catch ex As Exception
providerValue = GetExceptionType( ex )
End Try
Console.WriteLine( format, numericStr, _
defaultValue, providerValue )
End Sub
Sub Main( )
' Create a NumberFormatInfo object and set several of its
' properties that apply to numbers.
Dim provider As NumberFormatInfo = new NumberFormatInfo( )
' These properties affect the conversion.
provider.NegativeSign = "neg "
provider.PositiveSign = "pos "
' These properties do not affect the conversion.
' The input string cannot have decimal and group separators.
provider.NumberDecimalSeparator = "."
provider.NumberGroupSeparator = ","
provider.NumberGroupSizes = New Integer( ) { 3 }
provider.NumberNegativePattern = 0
Console.WriteLine( "This example of" & vbCrLf & _
" Convert.ToInt16( String ) and " & vbCrLf & _
" Convert.ToInt16( String, IFormatProvider ) " & _
vbCrLf & "generates the following output. It " & _
"converts several strings to " & vbCrLf & "Short " & _
"values, using default formatting " & _
"or a NumberFormatInfo object." & vbCrLf )
Console.WriteLine( format, "String to convert", _
"Default/exception", "Provider/exception" )
Console.WriteLine( format, "-----------------", _
"-----------------", "------------------" )
' Convert strings, with and without an IFormatProvider.
ConvertToInt16( "12345", provider )
ConvertToInt16( "+12345", provider )
ConvertToInt16( "pos 12345", provider )
ConvertToInt16( "-12345", provider )
ConvertToInt16( "neg 12345", provider )
ConvertToInt16( "12345.", provider )
ConvertToInt16( "12,345", provider )
ConvertToInt16( "(12345)", provider )
ConvertToInt16( "32768", provider )
ConvertToInt16( "-32769", provider )
End Sub
End Module
' This example of
' Convert.ToInt16( String ) and
' Convert.ToInt16( String, IFormatProvider )
' generates the following output. It converts several strings to
' Short values, using default formatting or a NumberFormatInfo object.
'
' String to convert Default/exception Provider/exception
' ----------------- ----------------- ------------------
' 12345 12345 12345
' +12345 12345 FormatException
' pos 12345 FormatException 12345
' -12345 -12345 FormatException
' neg 12345 FormatException -12345
' 12345. FormatException FormatException
' 12,345 FormatException FormatException
' (12345) FormatException FormatException
' 32768 OverflowException OverflowException
' -32769 OverflowException FormatException
开发者ID:VB.NET开发者,项目名称:System,代码行数:101,代码来源:Convert.ToInt16
示例3: IConvertibleProviderDemo
' 导入命名空间
Imports System.Collections
Module IConvertibleProviderDemo
' Define the types of averaging available in the class
' implementing IConvertible.
Enum AverageType as Short
None = 0
GeometricMean = 1
ArithmeticMean = 2
Median = 3
End Enum
' Pass an instance of this class to methods that require an
' IFormatProvider. The class instance determines the type of
' average to calculate.
Public Class AverageInfo
Implements IFormatProvider
Protected AvgType As AverageType
' Specify the type of averaging in the constructor.
Public Sub New( avgType As AverageType )
Me.AvgType = avgType
End Sub
' This method returns a reference to the containing object
' if an object of AverageInfo type is requested.
Public Function GetFormat( argType As Type ) As Object _
Implements IFormatProvider.GetFormat
If argType Is GetType( AverageInfo ) Then
Return Me
Else
Return Nothing
End If
End Function
' Use this property to set or get the type of averaging.
Public Property TypeOfAverage( ) As AverageType
Get
Return Me.AvgType
End Get
Set( ByVal value as AverageType )
Me.AvgType = value
End Set
End Property
End Class
' This class encapsulates an array of Double values and implements
' the IConvertible interface. Most of the IConvertible methods
' return an average of the array elements in one of three types:
' arithmetic mean, geometric mean, or median.
Public Class DataSet
Implements IConvertible
Protected data As ArrayList
Protected defaultProvider As AverageInfo
' Construct the object and add an initial list of values.
' Create a default format provider.
Public Sub New( ParamArray values( ) As Double )
data = New ArrayList( values )
defaultProvider = New AverageInfo( _
AverageType.ArithmeticMean )
End Sub
' Add additional values with this method.
Public Function Add( value As Double ) As Integer
data.Add( value )
Return data.Count
End Function
' Get, set, and add values with this indexer property.
Default Public Property Item(index As Integer) As Double
Get
If index >= 0 AndAlso index < data.Count Then
Return System.Convert.ToDouble( data( index ) )
Else
Throw New InvalidOperationException( _
"[DataSet.get] Index out of range." )
End If
End Get
Set
If index >= 0 AndAlso index < data.Count Then
data( index ) = value
ElseIf index = data.Count Then
data.Add( value )
Else
Throw New InvalidOperationException( _
"[DataSet.set] Index out of range." )
End If
End Set
End Property
' This property returns the number of elements in the object.
Public ReadOnly Property Count( ) As Integer
Get
Return data.Count
End Get
End Property
' This method calculates the average of the object's elements.
Protected Function Average( ByVal avgType As AverageType ) As Double
Dim SumProd As Double
Dim Index As Integer
If data.Count = 0 Then Return 0.0
Select Case avgType
Case AverageType.GeometricMean
SumProd = 1.0
For Index = 0 To data.Count - 1
SumProd *= data( Index )
Next Index
' This calculation will not fail with negative
' elements.
Return Math.Sign( SumProd ) * Math.Pow( _
Math.Abs( SumProd ), 1.0 / data.Count )
Case AverageType.ArithmeticMean
SumProd = 0.0
For Index = 0 To data.Count - 1
SumProd += data( Index )
Next Index
Return SumProd / data.Count
Case AverageType.Median
If data.Count Mod 2 = 0 Then
Return ( data( data.Count \ 2 ) + _
data( data.Count \ 2 - 1 ) ) / 2.0
Else
Return data( data.Count \ 2 )
End If
End Select
End Function
' Get the AverageInfo object from the caller's format
' provider, or use the local default.
Protected Function GetAverageInfo( _
provider As IFormatProvider ) As AverageInfo
Dim avgInfo As AverageInfo = Nothing
If Not provider Is Nothing Then
avgInfo = provider.GetFormat( GetType( AverageInfo ) )
End If
Return IIf( avgInfo Is Nothing, defaultProvider, avgInfo )
End Function
' Calculate the average and limit the range.
Protected Function CalcNLimitAverage( min As Double, _
max As Double, provider as IFormatProvider ) As Double
' Get the format provider and calculate the average.
Dim avgInfo As AverageInfo = GetAverageInfo( provider )
Dim avg As Double = Average( avgInfo.TypeOfAverage )
' Limit the range, based on the minimum and maximum values
' for the type.
Return IIf( avg > max, max, IIf( avg < min, min, avg ) )
End Function
' The following elements are required by IConvertible.
' None of these conversion functions throw exceptions. When
' the data is out of range for the type, the appropriate
' MinValue or MaxValue is used.
Public Function GetTypeCode( ) As TypeCode _
Implements IConvertible.GetTypeCode
Return TypeCode.Object
End Function
Function ToBoolean( ByVal provider As IFormatProvider ) As _
Boolean Implements IConvertible.ToBoolean
' ToBoolean is false if the dataset is empty.
If data.Count <= 0 Then
Return False
' For median averaging, ToBoolean is true if any
' non-discarded elements are nonzero.
ElseIf AverageType.Median = _
GetAverageInfo( provider ).TypeOfAverage Then
If data.Count Mod 2 = 0 Then
Return ( data( data.Count \ 2 ) <> 0.0 Or _
data( data.Count \ 2 - 1 ) <> 0.0 )
Else
Return data( data.Count \ 2 ) <> 0.0
End If
' For arithmetic or geometric mean averaging, ToBoolean is
' true if any element of the dataset is nonzero.
Else
Dim Index As Integer
For Index = 0 To data.Count - 1
If data( Index ) <> 0.0 Then Return True
Next Index
Return False
End If
End Function
Function ToByte( ByVal provider As IFormatProvider ) As Byte _
Implements IConvertible.ToByte
Return Convert.ToByte( CalcNLimitAverage( _
Byte.MinValue, Byte.MaxValue, provider ) )
End Function
Function ToChar( ByVal provider As IFormatProvider ) As Char _
Implements IConvertible.ToChar
Return Convert.ToChar( Convert.ToUInt16( _
CalcNLimitAverage( 0.0, &HFFFF, provider ) ) )
End Function
' Convert to DateTime by adding the calculated average as
' seconds to the current date and time. A valid DateTime is
' always returned.
Function ToDateTime( ByVal provider As IFormatProvider ) As _
DateTime Implements IConvertible.ToDateTime
Dim seconds As Double = Average( _
GetAverageInfo( provider ).TypeOfAverage )
Try
Return DateTime.Now.AddSeconds( seconds )
Catch ex As ArgumentOutOfRangeException
Return IIf( seconds < 0.0, DateTime.MinValue, _
DateTime.MaxValue )
End Try
End Function
Function ToDecimal( ByVal provider As IFormatProvider ) As _
Decimal Implements IConvertible.ToDecimal
' The Double conversion rounds Decimal.MinValue and
' Decimal.MaxValue to invalid Decimal values, so the
' following limits must be used.
Return Convert.ToDecimal( CalcNLimitAverage( _
-79228162514264330000000000000.0, _
79228162514264330000000000000.0, provider ) )
End Function
Function ToDouble( ByVal provider As IFormatProvider) As _
Double Implements IConvertible.ToDouble
Return Average( GetAverageInfo( provider ).TypeOfAverage )
End Function
Function ToInt16( ByVal provider As IFormatProvider ) As _
Short Implements IConvertible.ToInt16
Return Convert.ToInt16( CalcNLimitAverage( _
Int16.MinValue, Int16.MaxValue, provider ) )
End Function
Function ToInt32( ByVal provider As IFormatProvider ) As _
Integer Implements IConvertible.ToInt32
Return Convert.ToInt32( CalcNLimitAverage( _
Int32.MinValue, Int32.MaxValue, provider ) )
End Function
Function ToInt64( ByVal provider As IFormatProvider ) As Long _
Implements IConvertible.ToInt64
' The Double conversion rounds Int64.MinValue and
' Int64.MaxValue to invalid Long values, so the following
' limits must be used.
Return Convert.ToInt64( CalcNLimitAverage( _
-9223372036854775000, 9223372036854775000, provider ) )
End Function
Function ToSByte( ByVal provider As IFormatProvider ) As _
SByte Implements IConvertible.ToSByte
' SByte.MinValue and SByte.MaxValue are not defined in
' Visual Basic.
Return Convert.ToSByte( CalcNLimitAverage( _
-128, 127, provider ) )
End Function
Function ToSingle( ByVal provider As IFormatProvider ) As _
Single Implements IConvertible.ToSingle
Return Convert.ToSingle( CalcNLimitAverage( _
Single.MinValue, Single.MaxValue, provider ) )
End Function
Function ToUInt16( ByVal provider As IFormatProvider ) As _
UInt16 Implements IConvertible.ToUInt16
' UInt16.MinValue and UInt16.MaxValue are not defined in
' Visual Basic.
Return Convert.ToUInt16( CalcNLimitAverage( _
0, &HFFFF, provider ) )
End Function
Function ToUInt32( ByVal provider As IFormatProvider ) As _
UInt32 Implements IConvertible.ToUInt32
' UInt32.MinValue and UInt32.MaxValue are not defined in
' Visual Basic.
Return Convert.ToUInt32( CalcNLimitAverage( _
0, 4294967295, provider ) )
End Function
Function ToUInt64( ByVal provider As IFormatProvider ) As _
UInt64 Implements IConvertible.ToUInt64
' UInt64.MinValue and UInt64.MaxValue are not defined in
' Visual Basic. The Double conversion would have rounded
' UInt64.MaxValue, so the following limit must be used.
Return Convert.ToUInt64( CalcNLimitAverage( _
0, 18446744073709550000.0, provider ) )
End Function
Function ToType( ByVal conversionType As Type, _
ByVal provider As IFormatProvider) As Object _
Implements IConvertible.ToType
Return Convert.ChangeType( Average( GetAverageInfo( _
provider ).TypeOfAverage ), conversionType )
End Function
Overloads Function ToString( ByVal provider As IFormatProvider _
) As String Implements IConvertible.ToString
Dim avgType as AverageType = _
GetAverageInfo( provider ).TypeOfAverage
Return String.Format( "( {0}: {1:G10} )", avgType, _
Average( avgType ) )
End Function
End Class
' Display a DataSet with three different format providers.
Sub DisplayDataSet( ds As DataSet )
Dim fmt As String = "{0,-12}{1,20}{2,20}{3,20}"
Dim median As AverageInfo = New AverageInfo( AverageType.Median )
Dim geMean As AverageInfo = _
New AverageInfo( AverageType.GeometricMean )
Dim iX As Integer
' Display the dataset elements.
If ds.Count > 0 Then
Console.Write( vbCrLf & "DataSet: [{0}", ds( 0 ) )
For iX = 1 To ds.Count - 1
Console.Write( ", {0}", ds( iX ) )
Next iX
Console.WriteLine( "]" & vbCrLf )
End If
Console.WriteLine( fmt, "Convert.", "Default", _
"Geometric Mean", "Median" )
Console.WriteLine( fmt, "--------", "-------", _
"--------------", "------" )
Console.WriteLine( fmt, "ToBoolean", _
Convert.ToBoolean( ds, Nothing ), _
Convert.ToBoolean( ds, geMean ), _
Convert.ToBoolean( ds, median ) )
Console.WriteLine( fmt, "ToByte", _
Convert.ToByte( ds, Nothing ), _
Convert.ToByte( ds, geMean ), _
Convert.ToByte( ds, median ) )
Console.WriteLine( fmt, "ToChar", _
Convert.ToChar( ds, Nothing ), _
Convert.ToChar( ds, geMean ), _
Convert.ToChar( ds, median ) )
Console.WriteLine( "{0,-12}{1,20:yyyy-MM-dd HH:mm:ss}" & _
"{2,20:yyyy-MM-dd HH:mm:ss}{3,20:yyyy-MM-dd HH:mm:ss}", _
"ToDateTime", Convert.ToDateTime( ds, Nothing ), _
Convert.ToDateTime( ds, geMean ), _
Convert.ToDateTime( ds, median ) )
Console.WriteLine( fmt, "ToDecimal", _
Convert.ToDecimal( ds, Nothing ), _
Convert.ToDecimal( ds, geMean ), _
Convert.ToDecimal( ds, median ) )
Console.WriteLine( fmt, "ToDouble", _
Convert.ToDouble( ds, Nothing ), _
Convert.ToDouble( ds, geMean ), _
Convert.ToDouble( ds, median ) )
Console.WriteLine( fmt, "ToInt16", _
Convert.ToInt16( ds, Nothing ), _
Convert.ToInt16( ds, geMean ), _
Convert.ToInt16( ds, median ) )
Console.WriteLine( fmt, "ToInt32", _
Convert.ToInt32( ds, Nothing ), _
Convert.ToInt32( ds, geMean ), _
Convert.ToInt32( ds, median ) )
Console.WriteLine( fmt, "ToInt64", _
Convert.ToInt64( ds, Nothing ), _
Convert.ToInt64( ds, geMean ), _
Convert.ToInt64( ds, median ) )
Console.WriteLine( fmt, "ToSByte", _
Convert.ToSByte( ds, Nothing ), _
Convert.ToSByte( ds, geMean ), _
Convert.ToSByte( ds, median ) )
Console.WriteLine( fmt, "ToSingle", _
Convert.ToSingle( ds, Nothing ), _
Convert.ToSingle( ds, geMean ), _
Convert.ToSingle( ds, median ) )
Console.WriteLine( fmt, "ToUInt16", _
Convert.ToUInt16( ds, Nothing ), _
Convert.ToUInt16( ds, geMean ), _
Convert.ToUInt16( ds, median ) )
Console.WriteLine( fmt, "ToUInt32", _
Convert.ToUInt32( ds, Nothing ), _
Convert.ToUInt32( ds, geMean ), _
Convert.ToUInt32( ds, median ) )
Console.WriteLine( fmt, "ToUInt64", _
Convert.ToUInt64( ds, Nothing ), _
Convert.ToUInt64( ds, geMean ), _
Convert.ToUInt64( ds, median ) )
End Sub
Sub Main( )
Console.WriteLine( _
"This example of the Convert.To<Type>( Object, " & _
"IFormatProvider ) methods " & vbCrLf & "generates " & _
"the following output. The example displays the " & _
"values " & vbCrLf & "returned by the methods, " & _
"using several IFormatProvider objects." & vbCrLf )
Dim ds1 As New DataSet( 10.5, 22.2, 45.9, 88.7, 156.05, 297.6 )
DisplayDataSet( ds1 )
Dim ds2 As New DataSet( _
359999.95, 425000, 499999.5, 775000, 1695000 )
DisplayDataSet( ds2 )
End Sub
End Module
' This example of the Convert.To<Type>( Object, IFormatProvider ) methods
' generates the following output. The example displays the values
' returned by the methods, using several IFormatProvider objects.
'
' DataSet: [10.5, 22.2, 45.9, 88.7, 156.05, 297.6]
'
' Convert. Default Geometric Mean Median
' -------- ------- -------------- ------
' ToBoolean True True True
' ToByte 103 59 67
' ToChar g ; C
' ToDateTime 2003-05-13 14:52:53 2003-05-13 14:52:09 2003-05-13 14:52:17
' ToDecimal 103.491666666667 59.4332135445164 67.3
' ToDouble 103.491666666667 59.4332135445164 67.3
' ToInt16 103 59 67
' ToInt32 103 59 67
' ToInt64 103 59 67
' ToSByte 103 59 67
' ToSingle 103.4917 59.43321 67.3
' ToUInt16 103 59 67
' ToUInt32 103 59 67
' ToUInt64 103 59 67
'
' DataSet: [359999.95, 425000, 499999.5, 775000, 1695000]
'
' Convert. Default Geometric Mean Median
' -------- ------- -------------- ------
' ToBoolean True True True
' ToByte 255 255 255
' ToChar ? ? ?
' ToDateTime 2003-05-22 07:27:49 2003-05-20 22:17:27 2003-05-19 09:44:29
' ToDecimal 750999.89 631577.237188435 499999.5
' ToDouble 750999.89 631577.237188435 499999.5
' ToInt16 32767 32767 32767
' ToInt32 751000 631577 500000
' ToInt64 751000 631577 500000
' ToSByte 127 127 127
' ToSingle 750999.9 631577.3 499999.5
' ToUInt16 65535 65535 65535
' ToUInt32 751000 631577 500000
' ToUInt64 751000 631577 500000
开发者ID:VB.NET开发者,项目名称:System,代码行数:478,代码来源:Convert.ToInt16
示例4: numbers
Dim numbers() As ULong = { UInt64.MinValue, 121, 340, UInt64.MaxValue }
Dim result As Short
For Each number As ULong In numbers
Try
result = Convert.ToInt16(number)
Console.WriteLine("Converted the {0} value {1} to a {2} value {3}.", _
number.GetType().Name, number, _
result.GetType().Name, result)
Catch e As OverflowException
Console.WriteLine("The {0} value {1} is outside the range of the Int16 type.", _
number.GetType().Name, number)
End Try
Next
开发者ID:VB.NET开发者,项目名称:System,代码行数:13,代码来源:Convert.ToInt16 输出:
Converted the UInt64 value 0 to a Int16 value 0.
Converted the UInt64 value 121 to a Int16 value 121.
Converted the UInt64 value 340 to a Int16 value 340.
The UInt64 value 18446744073709551615 is outside the range of the Int16 type.
示例5: numbers
Dim numbers() As UInteger = { UInt32.MinValue, 121, 340, UInt32.MaxValue }
Dim result As Short
For Each number As UInteger In numbers
Try
result = Convert.ToInt16(number)
Console.WriteLine("Converted the {0} value {1} to a {2} value {3}.", _
number.GetType().Name, number, _
result.GetType().Name, result)
Catch e As OverflowException
Console.WriteLine("The {0} value {1} is outside the range of the Int16 type.", _
number.GetType().Name, number)
End Try
Next
开发者ID:VB.NET开发者,项目名称:System,代码行数:13,代码来源:Convert.ToInt16 输出:
Converted the UInt32 value 0 to a Int16 value 0.
Converted the UInt32 value 121 to a Int16 value 121.
Converted the UInt32 value 340 to a Int16 value 340.
The UInt32 value 4294967295 is outside the range of the Int16 type.
示例6: numbers
Dim numbers() As UShort = { UInt16.MinValue, 121, 340, UInt16.MaxValue }
Dim result As Short
For Each number As UShort In numbers
Try
result = Convert.ToInt16(number)
Console.WriteLine("Converted the {0} value {1} to a {2} value {3}.", _
number.GetType().Name, number, _
result.GetType().Name, result)
Catch e As OverflowException
Console.WriteLine("The {0} value {1} is outside the range of the Int16 type.", _
number.GetType().Name, number)
End Try
Next
开发者ID:VB.NET开发者,项目名称:System,代码行数:13,代码来源:Convert.ToInt16 输出:
Converted the UInt16 value 0 to a Int16 value 0.
Converted the UInt16 value 121 to a Int16 value 121.
Converted the UInt16 value 340 to a Int16 value 340.
The UInt16 value 65535 is outside the range of the Int16 type.
示例7: values
Dim values() As Single = { Single.MinValue, -1.38e10, -1023.299, -12.98, _
0, 9.113e-16, 103.919, 17834.191, Single.MaxValue }
Dim result As Short
For Each value As Single In values
Try
result = Convert.ToInt16(value)
Console.WriteLine("Converted the {0} value {1} to the {2} value {3}.", _
value.GetType().Name, value, result.GetType().Name, result)
Catch e As OverflowException
Console.WriteLine("{0} is outside the range of the Int16 type.", value)
End Try
Next
开发者ID:VB.NET开发者,项目名称:System,代码行数:13,代码来源:Convert.ToInt16 输出:
-3.40282346638529E+38 is outside the range of the Int16 type.
-13799999488 is outside the range of the Int16 type.
Converted the Double value -1023.29901123047 to the Int16 value -1023.
Converted the Double value -12.9799995422363 to the Int16 value -13.
Converted the Double value 0 to the Int16 value 0.
Converted the Double value 9.11299983940444E-16 to the Int16 value 0.
Converted the Double value 103.918998718262 to the Int16 value 104.
Converted the Double value 17834.19140625 to the Int16 value 17834.
3.40282346638529E+38 is outside the range of the Int16 type.
示例8: Example
Module Example
Public Sub Main()
Dim hexStrings() As String = { "8000", "0FFF", "f000", "00A30", "D", _
"-13", "9AC61", "GAD" }
For Each hexString As String In hexStrings
Try
Dim number As Short = Convert.ToInt16(hexString, 16)
Console.WriteLine("Converted '{0}' to {1:N0}.", hexString, number)
Catch e As FormatException
Console.WriteLine("'{0}' is not in the correct format for a hexadecimal number.", _
hexString)
Catch e As OverflowException
Console.WriteLine("'{0}' is outside the range of an Int16.", hexString)
Catch e As ArgumentException
Console.WriteLine("'{0}' is invalid in base 16.", hexString)
End Try
Next
End Sub
End Module
开发者ID:VB.NET开发者,项目名称:System,代码行数:19,代码来源:Convert.ToInt16 输出:
Converted '8000' to -32,768.
Converted '0FFF' to 4,095.
Converted 'f000' to -4,096.
Converted '00A30' to 2,608.
Converted 'D' to 13.
-13' is invalid in base 16.
9AC61' is outside the range of an Int16.
GAD' is not in the correct format for a hexadecimal number.
示例9:
' Create a hexadecimal value out of range of the Int16 type.
Dim value As String = Convert.ToString(CInt(Short.MaxValue) + 1, 16)
' Convert it back to a number.
Try
Dim number As Short = Convert.ToInt16(value, 16)
Console.WriteLine("0x{0} converts to {1}.", value, number)
Catch e As OverflowException
Console.WriteLine("Unable to convert '0x{0}' to a 16-bit integer.", value)
End Try
开发者ID:VB.NET开发者,项目名称:System,代码行数:9,代码来源:Convert.ToInt16
示例10: CInt
' Create a hexadecimal value out of range of the Short type.
Dim sourceNumber As Integer = CInt(Short.MaxValue) + 1
Dim isNegative As Boolean = (Math.Sign(sourceNumber) = -1)
Dim value As String = Convert.ToString(sourceNumber, 16)
Dim targetNumber As Short
Try
targetNumber = Convert.ToInt16(value, 16)
If Not isNegative And ((targetNumber And &H8000) <> 0) Then
Throw New OverflowException()
Else
Console.WriteLine("0x{0} converts to {1}.", value, targetNumber)
End If
Catch e As OverflowException
Console.WriteLine("Unable to convert '0x{0}' to a 16-bit integer.", value)
End Try
' Displays the following to the console:
' Unable to convert '0x8000' to a 16-bit integer.
开发者ID:VB.NET开发者,项目名称:System,代码行数:17,代码来源:Convert.ToInt16
示例11: values
Dim values() As Object = { True, -12, 163, 935, "x"c, #5/12/2009#, _
"104", "103.0", "-1", _
"1.00e2", "One", 1.00e2}
Dim result As Short
For Each value As Object In values
Try
result = Convert.ToInt16(value)
Console.WriteLine("Converted the {0} value {1} to the {2} value {3}.", _
value.GetType().Name, value, _
result.GetType().Name, result)
Catch e As OverflowException
Console.WriteLine("The {0} value {1} is outside the range of the Int16 type.", _
value.GetType().Name, value)
Catch e As FormatException
Console.WriteLine("The {0} value {1} is not in a recognizable format.", _
value.GetType().Name, value)
Catch e As InvalidCastException
Console.WriteLine("No conversion to an Int16 exists for the {0} value {1}.", _
value.GetType().Name, value)
End Try
Next
开发者ID:VB.NET开发者,项目名称:System,代码行数:23,代码来源:Convert.ToInt16 输出:
Converted the Boolean value True to the Int16 value 1.
Converted the Int32 value -12 to the Int16 value -12.
Converted the Int32 value 163 to the Int16 value 163.
Converted the Int32 value 935 to the Int16 value 935.
Converted the Char value x to the Int16 value 120.
No conversion to an Int16 exists for the DateTime value 5/12/2009 12:00:00 AM.
Converted the String value 104 to the Int16 value 104.
The String value 103.0 is not in a recognizable format.
Converted the String value -1 to the Int16 value -1.
The String value 1.00e2 is not in a recognizable format.
The String value One is not in a recognizable format.
Converted the Double value 100 to the Int16 value 100.
示例12: numbers
Dim numbers() As Integer = { Int32.MinValue, -1, 0, 121, 340, Int32.MaxValue }
Dim result As Short
For Each number As Integer In numbers
Try
result = Convert.ToInt16(number)
Console.WriteLine("Converted the {0} value {1} to a {2} value {3}.", _
number.GetType().Name, number, _
result.GetType().Name, result)
Catch e As OverflowException
Console.WriteLine("The {0} value {1} is outside the range of the Int16 type.", _
number.GetType().Name, number)
End Try
Next
开发者ID:VB.NET开发者,项目名称:System,代码行数:14,代码来源:Convert.ToInt16 输出:
The Int32 value -2147483648 is outside the range of the Int16 type.
Converted the Int32 value -1 to a Int16 value -1.
Converted the Int32 value 0 to a Int16 value 0.
Converted the Int32 value 121 to a Int16 value 121.
Converted the Int32 value 340 to a Int16 value 340.
The Int32 value 2147483647 is outside the range of the Int16 type.
示例13: values
Dim values() As Double = { Double.MinValue, -1.38e10, -1023.299, -12.98, _
0, 9.113e-16, 103.919, 17834.191, Double.MaxValue }
Dim result As Short
For Each value As Double In values
Try
result = Convert.ToInt16(value)
Console.WriteLine("Converted {0} to {1}.", value, result)
Catch e As OverflowException
Console.WriteLine("{0} is outside the range of the Int16 type.", value)
End Try
Next
' -1.79769313486232E+308 is outside the range of the Int16 type.
' -13800000000 is outside the range of the Int16 type.
' Converted -1023.299 to -1023.
' Converted -12.98 to -13.
' Converted 0 to 0.
' Converted 9.113E-16 to 0.
' Converted 103.919 to 104.
' Converted 17834.191 to 17834.
' 1.79769313486232E+308 is outside the range of the Int16 type.
开发者ID:VB.NET开发者,项目名称:System,代码行数:21,代码来源:Convert.ToInt16
示例14: values
Dim values() As Decimal = { Decimal.MinValue, -1034.23d, -12d, 0d, 147d, _
9214.16d, Decimal.MaxValue }
Dim result As Short
For Each value As Decimal In values
Try
result = Convert.ToInt16(value)
Console.WriteLine("Converted {0} to {1}.", value, result)
Catch e As OverflowException
Console.WriteLine("{0} is outside the range of the Int16 type.", _
value)
End Try
Next
开发者ID:VB.NET开发者,项目名称:System,代码行数:13,代码来源:Convert.ToInt16 输出:
-79228162514264337593543950335 is outside the range of the Int16 type.
Converted -1034.23 to -1034.
Converted -12 to -12.
Converted 0 to 0.
Converted 147 to 147.
Converted 9214.16 to 9214.
79228162514264337593543950335 is outside the range of the Int16 type.
示例15: chars
Dim chars() As Char = { "a"c, "z"c, ChrW(7), ChrW(1023), _
ChrW(Short.MaxValue), ChrW(&hFFFE) }
Dim result As Short
For Each ch As Char in chars
Try
result = Convert.ToInt16(ch)
Console.WriteLine("'{0}' converts to {1}.", ch, result)
Catch e As OverflowException
Console.WriteLine("Unable to convert u+{0} to an Int16.", _
AscW(ch).ToString("X4"))
End Try
Next
开发者ID:VB.NET开发者,项目名称:System,代码行数:13,代码来源:Convert.ToInt16 输出:
a' converts to 97.
z' converts to 122.
converts to 7.
?' converts to 1023.
?' converts to 32767.
Unable to convert u+FFFE to a UInt16.
示例16: bytes
Dim bytes() As Byte = { Byte.MinValue, 14, 122, Byte.MaxValue}
Dim result As Short
For Each byteValue As Byte In bytes
result = Convert.ToInt16(byteValue)
Console.WriteLine("The Byte value {0} converts to {1}.", _
byteValue, result)
Next
开发者ID:VB.NET开发者,项目名称:System,代码行数:8,代码来源:Convert.ToInt16 输出:
The Byte value 0 converts to 0.
The Byte value 14 converts to 14.
The Byte value 122 converts to 122.
The Byte value 255 converts to 255.
示例17:
Dim falseFlag As Boolean = False
Dim trueFlag As Boolean = True
Console.WriteLine("{0} converts to {1}.", falseFlag, _
Convert.ToInt16(falseFlag))
Console.WriteLine("{0} converts to {1}.", trueFlag, _
Convert.ToInt16(trueFlag))
开发者ID:VB.NET开发者,项目名称:System,代码行数:7,代码来源:Convert.ToInt16 输出:
False converts to 0.
True converts to 1.
示例18: numbers
Dim numbers() As Long = { Int64.MinValue, -1, 0, 121, 340, Int64.MaxValue }
Dim result As Short
For Each number As Long In numbers
Try
result = Convert.ToInt16(number)
Console.WriteLine("Converted the {0} value {1} to the {2} value {3}.", _
number.GetType().Name, number, _
result.GetType().Name, result)
Catch e As OverflowException
Console.WriteLine("The {0} value {1} is outside the range of the Int16 type.", _
number.GetType().Name, number)
End Try
Next
开发者ID:VB.NET开发者,项目名称:System,代码行数:13,代码来源:Convert.ToInt16 输出:
The Int64 value -9223372036854775808 is outside the range of the Int16 type.
Converted the Int64 value -1 to the Int16 value -1.
Converted the Int64 value 0 to the Int16 value 0.
Converted the Int64 value 121 to the Int16 value 121.
Converted the Int64 value 340 to the Int16 value 340.
The Int64 value 9223372036854775807 is outside the range of the Int16 type.
注:本文中的System.Convert.ToInt16方法示例整理自Github/MSDocs等源码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。 |
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