VB.NET Math.Tanh方法代码示例

OStack程序员社区-中国程序员成长平台 › 门户 › 编程› VB.NET›VB.NET教程

原作者: [db:作者] 来自: [db:来源] 收藏邀请

本文整理汇总了VB.NET中System.Math.Tanh方法的典型用法代码示例。如果您正苦于以下问题：VB.NET Math.Tanh方法的具体用法？VB.NET Math.Tanh怎么用？VB.NET Math.Tanh使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类System.Math的用法示例。

在下文中一共展示了Math.Tanh方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于我们的系统推荐出更棒的VB.NET代码示例。

示例1: DemoTanh

' Example for the hyperbolic Math.Tanh( Double ) method.
Module DemoTanh
   
    Sub Main()
        Console.WriteLine( _
            "This example of hyperbolic Math.Tanh( Double )" & _
            vbCrLf & "generates the following output.")
        Console.WriteLine( _
            vbCrLf & "Evaluate these hyperbolic " & _
            "identities with selected values for X:")
        Console.WriteLine("   tanh(X) = sinh(X) / cosh(X)")
        Console.WriteLine("   tanh(2 * X) = 2 * tanh(X) / (1 + tanh^2(X))")
          
        UseTanh(0.1)
        UseTanh(1.2)
        UseTanh(4.9)
          
        Console.WriteLine( _
            vbCrLf & "Evaluate [tanh(X + Y) == (tanh(X) + " & _
            "tanh(Y)) / (1 + tanh(X) * tanh(Y))]" & _
            vbCrLf & "with selected values for X and Y:")

        UseTwoArgs(0.1, 1.2)
        UseTwoArgs(1.2, 4.9)
    End Sub
       
    ' Evaluate hyperbolic identities with a given argument.
    Sub UseTanh(arg As Double)
        Dim tanhArg As Double = Math.Tanh(arg)
          
        ' Evaluate tanh(X) = sinh(X) / cosh(X).
        Console.WriteLine( _
            vbCrLf & "                       Math.Tanh({0}) = {1:E16}" & _
            vbCrLf & "      Math.Sinh({0}) / Math.Cosh({0}) = {2:E16}", _
            arg, tanhArg, Math.Sinh(arg) / Math.Cosh(arg))
          
        ' Evaluate tanh(2 * X) = 2 * tanh(X) / (1 + tanh^2(X)).
        Console.WriteLine( _
            "                   2 * Math.Tanh({0}) /", _
            arg, 2.0 * tanhArg)
        Console.WriteLine( _
            "             (1 + (Math.Tanh({0}))^2) = {1:E16}", _
            arg, 2.0 * tanhArg /(1.0 + tanhArg * tanhArg))
        Console.WriteLine( _
            "                       Math.Tanh({0}) = {1:E16}", _
            2.0 * arg, Math.Tanh((2.0 * arg)))
    End Sub
       
    ' Evaluate a hyperbolic identity that is a function of two arguments.
    Sub UseTwoArgs(argX As Double, argY As Double)

        ' Evaluate tanh(X + Y) = (tanh(X) + tanh(Y)) / (1 + tanh(X) * tanh(Y)).
        Console.WriteLine( _
            vbCrLf & "    (Math.Tanh({0}) + Math.Tanh({1})) /" & _
            vbCrLf & "(1 + Math.Tanh({0}) * Math.Tanh({1})) = {2:E16}", _
            argX, argY, (Math.Tanh(argX) + Math.Tanh(argY)) / _
            (1.0 + Math.Tanh(argX) * Math.Tanh(argY)))
        Console.WriteLine( _
            "                       Math.Tanh({0}) = {1:E16}", _
            argX + argY, Math.Tanh(argX + argY))

    End Sub
End Module 'DemoTanh

' This example of hyperbolic Math.Tanh( Double )

开发者ID:VB.NET开发者，项目名称:System，代码行数:65，代码来源:Math.Tanh

输出：

Evaluate these hyperbolic identities with selected values for X:
tanh(X) = sinh(X) / cosh(X)
tanh(2 * X) = 2 * tanh(X) / (1 + tanh^2(X))

Math.Tanh(0.1) = 9.9667994624955819E-002
Math.Sinh(0.1) / Math.Cosh(0.1) = 9.9667994624955819E-002
2 * Math.Tanh(0.1) /
(1 + (Math.Tanh(0.1))^2) = 1.9737532022490401E-001
Math.Tanh(0.2) = 1.9737532022490401E-001

Math.Tanh(1.2) = 8.3365460701215521E-001
Math.Sinh(1.2) / Math.Cosh(1.2) = 8.3365460701215521E-001
2 * Math.Tanh(1.2) /
(1 + (Math.Tanh(1.2))^2) = 9.8367485769368024E-001
Math.Tanh(2.4) = 9.8367485769368024E-001

Math.Tanh(4.9) = 9.9988910295055444E-001
Math.Sinh(4.9) / Math.Cosh(4.9) = 9.9988910295055433E-001
2 * Math.Tanh(4.9) /
(1 + (Math.Tanh(4.9))^2) = 9.9999999385024030E-001
Math.Tanh(9.8) = 9.9999999385024030E-001

Evaluate [tanh(X + Y) == (tanh(X) + tanh(Y)) / (1 + tanh(X) * tanh(Y))]
with selected values for X and Y:

(Math.Tanh(0.1) + Math.Tanh(1.2)) /
(1 + Math.Tanh(0.1) * Math.Tanh(1.2)) = 8.6172315931330645E-001
Math.Tanh(1.3) = 8.6172315931330634E-001

(Math.Tanh(1.2) + Math.Tanh(4.9)) /
(1 + Math.Tanh(1.2) * Math.Tanh(4.9)) = 9.9998993913939649E-001
Math.Tanh(6.1) = 9.9998993913939649E-001

注：本文中的System.Math.Tanh方法示例整理自Github/MSDocs等源码及文档管理平台，相关代码片段筛选自各路编程大神贡献的开源项目，源码版权归原作者所有，传播和使用请参考对应项目的License；未经允许，请勿转载。