TypeScript NodeType.isBr函数代码示例

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本文整理汇总了TypeScript中tinymce/core/dom/NodeType.isBr函数的典型用法代码示例。如果您正苦于以下问题：TypeScript isBr函数的具体用法？TypeScript isBr怎么用？TypeScript isBr使用的例子？那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。

在下文中一共展示了isBr函数的4个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于我们的系统推荐出更棒的TypeScript代码示例。

示例1: if

const getBreakType = (scope: HTMLElement, direction: HDirection, currentPos: CaretPosition, nextPos: CaretPosition): BreakType => {
  if (NodeType.isBr(nextPos.getNode(direction === HDirection.Forwards))) {
    return BreakType.Br;
  } else if (isInSameBlock(currentPos, nextPos) === false) {
    return BreakType.Block;
  } else {
    return BreakType.Wrap;
  }
};

开发者ID:danielpunkass，项目名称:tinymce，代码行数:9，代码来源:LineReader.ts

示例2: getPositionsUntil

const isAtTableCellLine = (getPositionsUntil, scope: HTMLElement, pos: CaretPosition) => {
  const lineInfo = getPositionsUntil(scope, pos);

  // Since we can't determine if the caret is on the above or below line in a word wrap break we asume it's always
  // on the below/above line based on direction. This will make the caret jump one line if you are at the end of the last
  // line and moving down or at the beginning of the second line moving up.
  if (startsWithWrapBreak(lineInfo) || (!NodeType.isBr(pos.getNode()) && startsWithBrBreak(lineInfo))) {
    return !hasNextBreak(getPositionsUntil, scope, lineInfo);
  } else {
    return lineInfo.breakAt.isNone();
  }
};

开发者ID:danielpunkass，项目名称:tinymce，代码行数:12，代码来源:TableNavigation.ts

示例3: CaretWalker

const getPositionsUntil = (predicate: CheckerPredicate, direction: HDirection, scope: HTMLElement, start: CaretPosition): LineInfo => {
  const caretWalker = CaretWalker(scope);
  let currentPos = start, nextPos: CaretPosition;
  const positions: CaretPosition[] = [];

  while (currentPos) {
    nextPos = walk(direction, caretWalker, currentPos);

    if (!nextPos) {
      break;
    }

    if (NodeType.isBr(nextPos.getNode(false))) {
      if (direction === HDirection.Forwards) {
        return { positions: flip(direction, positions).concat([nextPos]), breakType: BreakType.Br, breakAt: Option.some(nextPos) };
      } else {
        return { positions: flip(direction, positions), breakType: BreakType.Br, breakAt: Option.some(nextPos) };
      }
    }

    if (!nextPos.isVisible()) {
      currentPos = nextPos;
      continue;
    }

    if (predicate(currentPos, nextPos)) {
      const breakType = getBreakType(scope, direction, currentPos, nextPos);
      return { positions: flip(direction, positions), breakType, breakAt: Option.some(nextPos) };
    }

    positions.push(nextPos);
    currentPos = nextPos;
  }

  return { positions: flip(direction, positions), breakType: BreakType.Eol, breakAt: Option.none() };
};

开发者ID:danielpunkass，项目名称:tinymce，代码行数:36，代码来源:LineReader.ts

示例4: function

 suite.test('isBr', function () {
   LegacyUnit.strictEqual(NodeType.isBr(null), false);
   LegacyUnit.strictEqual(NodeType.isBr(document.createTextNode('x')), false);
   LegacyUnit.strictEqual(NodeType.isBr(document.createElement('br')), true);
   LegacyUnit.strictEqual(NodeType.isBr(document.createComment('x')), false);
 });

开发者ID:abstask，项目名称:tinymce，代码行数:6，代码来源:NodeTypeTest.ts

注：本文中的tinymce/core/dom/NodeType.isBr函数示例由纯净天空整理自Github/MSDocs等源码及文档管理平台，相关代码片段筛选自各路编程大神贡献的开源项目，源码版权归原作者所有，传播和使用请参考对应项目的License；未经允许，请勿转载。